Paramagnetism — Question 2

Section 32-9 · Physics pages 5334–5335

Question 2 Continuous orientations introduce a factor of one-third in the Curie response Compare classical freely oriented moments of magnitude mu with a two-state projection model. For the classical model, set u = cos θ and use Z = 2π ∫1 −1 exudu, where x = µB/(kBT). Assume weak magnetization, so B is approximately mu0H. B µ θ continuous solid-angle orientations Schematic; labels, not drawing lengths, specify the data. (a) Derive the classical mean field-axis moment using the logarithmic derivative of Z. (b) Expand at small x and compare classical susceptibility with the two-state result from tanh x.
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Question 2 - Solution Continuous orientations introduce a factor of one-third in the Curie response B µ θ continuous solid-angle orientations (a) Method and calculation Z = 4πsinh x x , ⟨µz⟩= µ∂x ln Z. ⟨µz⟩= µ(coth x −1/x) . (b) Interpretation and further calculation coth x −1/x = x/3 + O(x3) ⇒χclassical = µ0nµ2 3kBT . tanh x = x + O(x3) ⇒χtwo−state = µ0nµ2 kBT = 3χclassical . Physical check The two models have different allowed orientations; the factor of three is not a unit conversion or an error in the Boltzmann weights.

Question 2

Continuous orientations introduce a factor of one-third in the Curie response

Compare classical freely oriented moments of magnitude mu with a two-state projection model. For the classical model, set u=cos⁡θu=\cos\theta and use Z=2π∫−11exuduZ=2\pi\int_{-1}^{1}e^{xu}du, where x=μB/(kBT)x=\mu B/(k_BT). Assume weak magnetization, so B is approximately mu0H.

Diagram shown in the original SVG worksheet.

  1. Derive the classical mean field-axis moment using the logarithmic derivative of Z.

  2. Expand at small x and compare classical susceptibility with the two-state result from tanh x.

Question 2 - Solution

Continuous orientations introduce a factor of one-third in the Curie response

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Z=4πsinh⁡xx,⟨μz⟩=μ∂xln⁡Z.Z=4\pi\frac{\sinh x}{x},\quad\langle\mu_z\rangle=\mu\partial_x\ln Z.⟨μz⟩=μ(coth⁡x−1/x).\boxed{\langle\mu_z\rangle=\mu(\coth x-1/x)}.

(b) Interpretation and further calculation

coth⁡x−1/x=x/3+O(x3)⇒χclassical=μ0nμ23kBT.\coth x-1/x=x/3+O(x^3)\Rightarrow\boxed{\chi_{\mathrm{classical}}=\frac{\mu_0n\mu^2}{3k_BT}}.tanh⁡x=x+O(x3)⇒χtwo−state=μ0nμ2kBT=3χclassical.\tanh x=x+O(x^3)\Rightarrow\boxed{\chi_{\mathrm{two-state}}=\frac{\mu_0n\mu^2}{k_BT}=3\chi_{\mathrm{classical}}}.

Physical check

The two models have different allowed orientations; the factor of three is not a unit conversion or an error in the Boltzmann weights.