Diamagnetism — Question 9

Section 32-8 · Physics pages 5328–5329

Question 9 Flux freezing and equilibrium flux expulsion predict different histories A simply connected sample initially contains uniform induction Bi through an interior material loop of area A. Compare two idealizations after cooling in the maintained applied field: a perfect conductor with E=0, and a reversible Meissner state with negligible penetration depth and interior B=0. No trapped vortices are present. Φi = BiA interior material loop Schematic; labels, not drawing lengths, specify the data. (a) Use Faraday law to determine the final loop flux in each model. (b) If cooling takes time tau, find the average electric circulation needed for the Meissner flux change, using the initial flux as positive.
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Question 9 - Solution Flux freezing and equilibrium flux expulsion predict different histories Φi = BiA interior material loop (a) Method and calculation E = 0 ⇒dΦ dt = − I E · dℓ= 0 ⇒Φconductor = BiA . BMeissner = 0 ⇒ΦMeissner = 0 . (b) Interpretation and further calculation Z τ 0 I E · dℓdt = −∆Φ = BiA. I E · dℓ  = BiA/τ . Physical check Zero resistance alone preserves the initial flux; equilibrium expulsion requires a transient electric circulation while the flux changes.

Question 9

Flux freezing and equilibrium flux expulsion predict different histories

A simply connected sample initially contains uniform induction Bi through an interior material loop of area A. Compare two idealizations after cooling in the maintained applied field: a perfect conductor with E=0, and a reversible Meissner state with negligible penetration depth and interior B=0. No trapped vortices are present.

Diagram shown in the original SVG worksheet.

  1. Use Faraday law to determine the final loop flux in each model.

  2. If cooling takes time tau, find the average electric circulation needed for the Meissner flux change, using the initial flux as positive.

Question 9 - Solution

Flux freezing and equilibrium flux expulsion predict different histories

Diagram shown in the original SVG worksheet.

(a) Method and calculation

E=0⇒dΦdt=−∮𝑬⋅dℓ=0⇒Φconductor=BiA.E=0\Rightarrow\frac{d\Phi}{dt}=-\oint\mathbf E\cdot d\boldsymbol\ell=0\Rightarrow\boxed{\Phi_{\mathrm{conductor}}=B_iA}.BMeissner=0⇒ΦMeissner=0.B_{\mathrm{Meissner}}=0\Rightarrow\boxed{\Phi_{\mathrm{Meissner}}=0}.

(b) Interpretation and further calculation

∫0τ∮𝑬⋅dℓdt=−ΔΦ=BiA.\int_0^\tau\oint\mathbf E\cdot d\boldsymbol\ell\,dt=-\Delta\Phi=B_iA.⟨∮𝑬⋅dℓ⟩=BiA/τ.\boxed{\left\langle\oint\mathbf E\cdot d\boldsymbol\ell\right\rangle=B_iA/\tau}.

Physical check

Zero resistance alone preserves the initial flux; equilibrium expulsion requires a transient electric circulation while the flux changes.