Diamagnetism — Question 2

Section 32-8 · Physics pages 5314–5315

Question 2 An induced orbital current gives a negative susceptibility in a constrained model In a constrained classical model an electron of charge -e moves on a fixed circular path of radius r. A slowly changing axial field B induces an azimuthal electric field. Only the change from its initial angular speed is considered; ignore radiation and changes of radius. δω ⊙B induced current: clockwise Schematic; labels, not drawing lengths, specify the data. (a) Use Faraday law and the tangential equation of motion to find the change of angular speed when B grows from zero. (b) Find the induced moment and susceptibility of number density n of identical such loops, using B approximately equal to mu0H.
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Question 2 - Solution An induced orbital current gives a negative susceptibility in a constrained model δω ⊙B induced current: clockwise (a) Method and calculation 2πrEϕ = −πr2 ˙B, mer δ ˙ω = −eEϕ = er ˙B/2. δω = eB/(2me) . (b) Interpretation and further calculation δµz = δIπr2 = −e δω 2π πr2 = −e2r2B 4me . χ = nδµz H ≃−µ0ne2r2 4me . Physical check This explicitly constrained orbit response illustrates induction; it is not a classical thermal-equilibrium theory of atomic magnetism.

Question 2

An induced orbital current gives a negative susceptibility in a constrained model

In a constrained classical model an electron of charge -e moves on a fixed circular path of radius r. A slowly changing axial field B induces an azimuthal electric field. Only the change from its initial angular speed is considered; ignore radiation and changes of radius.

Diagram shown in the original SVG worksheet.

  1. Use Faraday law and the tangential equation of motion to find the change of angular speed when B grows from zero.

  2. Find the induced moment and susceptibility of number density n of identical such loops, using B approximately equal to mu0H.

Question 2 - Solution

An induced orbital current gives a negative susceptibility in a constrained model

Diagram shown in the original SVG worksheet.

(a) Method and calculation

2πrEϕ=−πr2Ḃ,merδω̇=−eEϕ=erḂ/2.2\pi rE_\phi=-\pi r^2\dot B,\quad m_er\,\delta\dot\omega=-eE_\phi=er\dot B/2.δω=eB/(2me).\boxed{\delta\omega=eB/(2m_e)}.

(b) Interpretation and further calculation

δμz=δIπr2=−eδω2ππr2=−e2r2B4me.\delta\mu_z=\delta I\pi r^2=-\frac{e\,\delta\omega}{2\pi}\pi r^2=\boxed{-\frac{e^2r^2B}{4m_e}}.χ=nδμzH≃−μ0ne2r24me.\boxed{\chi=\frac{n\delta\mu_z}{H}\simeq-\frac{\mu_0ne^2r^2}{4m_e}}.

Physical check

This explicitly constrained orbit response illustrates induction; it is not a classical thermal-equilibrium theory of atomic magnetism.