Magnetic Materials — Question 6

Section 32-7 · Physics pages 5302–5303

Question 6 Layer orientation changes the effective magnetic permeability A laminate contains volume fractions f and 1-f of linear media with permeabilities mu1 and mu2. Layers are much thinner than the sample; neglect edges and free interface currents. ∥⊥ Schematic; labels, not drawing lengths, specify the data. (a) Derive effective permeability for a uniform field parallel to the layers. (b) Derive it for a field normal to the layers and evaluate both for f=1/2 and mu2=9mu1.
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Question 6 - Solution Layer orientation changes the effective magnetic permeability ∥⊥ (a) Method and calculation H1t = H2t = H ⇒⟨B⟩= [fµ1 + (1 −f)µ2]H. µ∥= fµ1 + (1 −f)µ2 = 5µ1 . (b) Interpretation and further calculation B1n = B2n = B ⇒⟨H⟩= B[f/µ1 + (1 −f)/µ2]. µ⊥= [f/µ1 + (1 −f)/µ2]−1 = 1.8µ1 . Physical check The arithmetic and harmonic means differ because continuity fixes different field components in the two orientations.

Question 6

Layer orientation changes the effective magnetic permeability

A laminate contains volume fractions f and 1-f of linear media with permeabilities mu1 and mu2. Layers are much thinner than the sample; neglect edges and free interface currents.

Diagram shown in the original SVG worksheet.

  1. Derive effective permeability for a uniform field parallel to the layers.

  2. Derive it for a field normal to the layers and evaluate both for f=1/2 and mu2=9mu1.

Question 6 - Solution

Layer orientation changes the effective magnetic permeability

Diagram shown in the original SVG worksheet.

(a) Method and calculation

H1t=H2t=H⇒⟨B⟩=[fμ1+(1−f)μ2]H.H_{1t}=H_{2t}=H\Rightarrow\langle B\rangle=[f\mu_1+(1-f)\mu_2]H.μ∥=fμ1+(1−f)μ2=5μ1.\boxed{\mu_\parallel=f\mu_1+(1-f)\mu_2=5\mu_1}.

(b) Interpretation and further calculation

B1n=B2n=B⇒⟨H⟩=B[f/μ1+(1−f)/μ2].B_{1n}=B_{2n}=B\Rightarrow\langle H\rangle=B[f/\mu_1+(1-f)/\mu_2].μ⟂=[f/μ1+(1−f)/μ2]−1=1.8μ1.\boxed{\mu_\perp=[f/\mu_1+(1-f)/\mu_2]^{-1}=1.8\mu_1}.

Physical check

The arithmetic and harmonic means differ because continuity fixes different field components in the two orientations.