Magnetic Materials — Question 4

Section 32-7 · Physics pages 5298–5299

Question 4 A highly permeable sphere still has a finite apparent susceptibility A linear sphere has N=1/3 and intrinsic susceptibility chi. Apply a uniform field Ha. Assume the linear model remains valid as chi is made large. M Ha Hd Schematic; labels, not drawing lengths, specify the data. (a) Find internal H and B in terms of Ha and chi. (b) Find the large-chi limits of M/Ha and B/(mu0Ha), and explain why internal H can vanish while B remains finite.
Show solutionHide solution
Question 4 - Solution A highly permeable sphere still has a finite apparent susceptibility M Ha Hd (a) Method and calculation H = Ha −M/3, M = χH ⇒H = Ha 1 + χ/3 . B = µ0Ha 1 + χ 1 + χ/3 . (b) Interpretation and further calculation lim χ→∞ M Ha = 3, lim χ→∞ B µ0Ha = 3. H →0, M →3Ha, B →µ0M = 3µ0Ha . Physical check This is a shape-limited linear-model result; a real ferromagnet may saturate before this limit is reached.

Question 4

A highly permeable sphere still has a finite apparent susceptibility

A linear sphere has N=1/3 and intrinsic susceptibility chi. Apply a uniform field Ha. Assume the linear model remains valid as chi is made large.

Diagram shown in the original SVG worksheet.

  1. Find internal H and B in terms of Ha and chi.

  2. Find the large-chi limits of M/Ha and B/(mu0Ha), and explain why internal H can vanish while B remains finite.

Question 4 - Solution

A highly permeable sphere still has a finite apparent susceptibility

Diagram shown in the original SVG worksheet.

(a) Method and calculation

H=Ha−M/3,M=χH⇒H=Ha1+χ/3.H=H_a-M/3,\quad M=\chi H\Rightarrow\boxed{H=\frac{H_a}{1+\chi/3}}.B=μ0Ha1+χ1+χ/3.\boxed{B=\mu_0H_a\frac{1+\chi}{1+\chi/3}}.

(b) Interpretation and further calculation

limχ→∞MHa=3,limχ→∞Bμ0Ha=3.\lim_{\chi\to\infty}\frac{M}{H_a}=3,\qquad\lim_{\chi\to\infty}\frac{B}{\mu_0H_a}=3.H→0,M→3Ha,B→μ0M=3μ0Ha.\boxed{H\to0,\quad M\to3H_a,\quad B\to\mu_0M=3\mu_0H_a}.

Physical check

This is a shape-limited linear-model result; a real ferromagnet may saturate before this limit is reached.