Magnetic Materials — Question 2

Section 32-7 · Physics pages 5294–5295

Question 2 A long linear core separates free-current and bound-current contributions A very long solenoid has n turns per unit length, current I, and a homogeneous linear core of susceptibility chi. Neglect end effects and hysteresis. B ℓ N turns; cross section A Schematic; labels, not drawing lengths, specify the data. (a) Find H, M, B and the equivalent bound surface-current magnitude on the cylindrical core. (b) Find the reversible magnetic energy density and its ratio to the empty-solenoid value at the same current.
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Question 2 - Solution A long linear core separates free-current and bound-current contributions B ℓ N turns; cross section A (a) Method and calculation H = nI, M = χnI, B = µ0(1 + χ)nI . Kb = M × ˆn ⇒|Kb| = |χnI| . (b) Interpretation and further calculation u = ∫B 0 H(B′) dB′ = B2 2µ0(1 + χ) = 1 2BH. u/u0 = 1 + χ at fixed I. Physical check H is set by free current in this long-solenoid geometry; magnetization supplies an additional contribution to B.

Question 2

A long linear core separates free-current and bound-current contributions

A very long solenoid has n turns per unit length, current I, and a homogeneous linear core of susceptibility chi. Neglect end effects and hysteresis.

Diagram shown in the original SVG worksheet.

  1. Find H, M, B and the equivalent bound surface-current magnitude on the cylindrical core.

  2. Find the reversible magnetic energy density and its ratio to the empty-solenoid value at the same current.

Question 2 - Solution

A long linear core separates free-current and bound-current contributions

Diagram shown in the original SVG worksheet.

(a) Method and calculation

H=nI,M=χnI,B=μ0(1+χ)nI.H=nI,\quad M=\chi nI,\quad\boxed{B=\mu_0(1+\chi)nI}.𝑲b=𝑴×n̂⇒|Kb|=|χnI|.\mathbf K_b=\mathbf M\times\hat n\Rightarrow\boxed{|K_b|=|\chi nI|}.

(b) Interpretation and further calculation

u=∫0BH(B′)dB′=B22μ0(1+χ)=12BH.u=\int_0^B H(B^{\prime})\,dB^{\prime}=\frac{B^2}{2\mu_0(1+\chi)}=\frac12BH.u/u0=1+χat fixed I.\boxed{u/u_0=1+\chi}\quad\text{at fixed }I.

Physical check

H is set by free current in this long-solenoid geometry; magnetization supplies an additional contribution to B.