Magnetism and Electrons — Question 10

Section 32-6 · Physics pages 5290–5291

Question 10 A thermal-energy comparison tests whether spin alignment can be strong For a noninteracting electron spin take moment projections ±µB in field B=1.00 T at T=300 K. Use µB = 9.274 × 10−24 J/T and kB = 1.381 × 10−23 J/K. Level populations obey Boltzmann weights. −µBB +µBB ∆E Schematic; labels, not drawing lengths, specify the data. (a) Find the ratio of the Zeeman gap to thermal energy and the lower-to-upper population ratio. (b) Find the temperature at which the gap equals kBT for the same field; explain what this comparison does and does not imply about alignment.
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Question 10 - Solution A thermal-energy comparison tests whether spin alignment can be strong −µBB +µBB ∆E (a) Method and calculation ∆E kBT = 2µBB kBT = 4.47695 × 10−3 . Nlower/Nupper = e∆E/(kBT) = 1.004487 . (b) Interpretation and further calculation ∆E = kBT∗⇒T∗= 2µBB/kB = 1.34308 K . T = T∗⇒Nlower/Nupper = e, Plower = e/(1 + e) ≃0.731 . Physical check An energy gap comparable to thermal energy gives a bias, not complete polarization; room-temperature populations here are nearly equal.

Question 10

A thermal-energy comparison tests whether spin alignment can be strong

For a noninteracting electron spin take moment projections ±μB\pm\mu_B in field B=1.00 T at T=300 K. Use μB=9.274×10−24\mu_B=9.274\times10^{-24} J/T and kB=1.381×10−23k_B=1.381\times10^{-23} J/K. Level populations obey Boltzmann weights.

Diagram shown in the original SVG worksheet.

  1. Find the ratio of the Zeeman gap to thermal energy and the lower-to-upper population ratio.

  2. Find the temperature at which the gap equals kBT for the same field; explain what this comparison does and does not imply about alignment.

Question 10 - Solution

A thermal-energy comparison tests whether spin alignment can be strong

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ΔEkBT=2μBBkBT=4.47695×10−3.\frac{\Delta E}{k_BT}=\frac{2\mu_BB}{k_BT}=\boxed{4.47695\times10^{-3}}.Nlower/Nupper=eΔE/(kBT)=1.004487.\boxed{N_{\mathrm{lower}}/N_{\mathrm{upper}}=e^{\Delta E/(k_BT)}=1.004487}.

(b) Interpretation and further calculation

ΔE=kBT*⇒T*=2μBB/kB=1.34308K.\Delta E=k_BT_*\Rightarrow\boxed{T_*=2\mu_BB/k_B=1.34308\,\mathrm K}.T=T*⇒Nlower/Nupper=e,Plower=e/(1+e)≃0.731.T=T_*\Rightarrow N_{\mathrm{lower}}/N_{\mathrm{upper}}=e,\quad\boxed{P_{\mathrm{lower}}=e/(1+e)\simeq0.731}.

Physical check

An energy gap comparable to thermal energy gives a bias, not complete polarization; room-temperature populations here are nearly equal.