Magnetism and Electrons — Question 1

Section 32-6 · Physics pages 5272–5273

Question 1 A classical electron orbit has opposite moment and angular momentum In a classical circular-orbit model an electron of charge -e and mass me moves counterclockwise, viewed from +z, at speed v and radius r. Use the conventional-current definition of magnetic moment. −e +z : ⊙L µ into page Schematic; labels, not drawing lengths, specify the data. (a) Derive the vector relation between orbital moment and angular momentum. (b) If radius doubles while angular momentum is conserved, find the new speed, current magnitude, and moment relative to their initial values.
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Question 1 - Solution A classical electron orbit has opposite moment and angular momentum −e +z : ⊙L µ into page (a) Method and calculation I = ev 2πr, µ = −Iπr2ˆz = −evr 2 ˆz. L = mevrˆz ⇒µ = −e 2me L . (b) Interpretation and further calculation r2 = 2r1, L2 = L1 ⇒v2 = v1/2, I2 = I1/4. µ2 = µ1 . Physical check The classical orbit is a model for deriving the gyromagnetic ratio, not a literal quantum electron trajectory.

Question 1

A classical electron orbit has opposite moment and angular momentum

In a classical circular-orbit model an electron of charge -e and mass me moves counterclockwise, viewed from +z, at speed v and radius r. Use the conventional-current definition of magnetic moment.

Diagram shown in the original SVG worksheet.

  1. Derive the vector relation between orbital moment and angular momentum.

  2. If radius doubles while angular momentum is conserved, find the new speed, current magnitude, and moment relative to their initial values.

Question 1 - Solution

A classical electron orbit has opposite moment and angular momentum

Diagram shown in the original SVG worksheet.

(a) Method and calculation

I=ev2πr,𝝁=−Iπr2ẑ=−evr2ẑ.I=\frac{ev}{2\pi r},\quad\boldsymbol\mu=-I\pi r^2\hat z=-\frac{evr}{2}\hat z.𝑳=mevrẑ⇒𝝁=−e2me𝑳.\mathbf L=m_evr\hat z\Rightarrow\boxed{\boldsymbol\mu=-\frac{e}{2m_e}\mathbf L}.

(b) Interpretation and further calculation

r2=2r1,L2=L1⇒v2=v1/2,I2=I1/4.r_2=2r_1,\ L_2=L_1\Rightarrow v_2=v_1/2,\quad I_2=I_1/4.𝝁2=𝝁1.\boxed{\boldsymbol\mu_2=\boldsymbol\mu_1}.

Physical check

The classical orbit is a model for deriving the gyromagnetic ratio, not a literal quantum electron trajectory.