Magnets — Question 8

Section 32-5 · Physics pages 5266–5267

Question 8 Equal axial and equatorial readings occur at unequal radii A small magnet produces far fields Ba = µ0m/(2πr3 a) on its axis and Be = µ0m/(4πr3 e) on its equator. Two probes read equal magnitudes Bstar. m axial opposite axial equatorial Schematic; labels, not drawing lengths, specify the data. (a) Find ra/re and infer m from Bstar and re. (b) A third probe lies on the opposite axial side at radius ra. Compare all three field directions for a moment along +z.
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Question 8 - Solution Equal axial and equatorial readings occur at unequal radii m axial opposite axial equatorial (a) Method and calculation 2 r3a = 1 r3e ⇒ra/re = 21/3 . m = 4πr3 eB∗/µ0 . (b) Interpretation and further calculation B+z = B∗ˆz, B−z = B∗ˆz. Bequator = −B∗ˆz . Physical check On the negative axial side the field points toward the dipole, but its vector still points along +z.

Question 8

Equal axial and equatorial readings occur at unequal radii

A small magnet produces far fields Ba=μ0m/(2πra3)B_a=\mu_0m/(2\pi r_a^3) on its axis and Be=μ0m/(4πre3)B_e=\mu_0m/(4\pi r_e^3) on its equator. Two probes read equal magnitudes Bstar.

Diagram shown in the original SVG worksheet.

  1. Find ra/re and infer m from Bstar and re.

  2. A third probe lies on the opposite axial side at radius ra. Compare all three field directions for a moment along +z.

Question 8 - Solution

Equal axial and equatorial readings occur at unequal radii

Diagram shown in the original SVG worksheet.

(a) Method and calculation

2ra3=1re3⇒ra/re=21/3.\frac{2}{r_a^3}=\frac{1}{r_e^3}\Rightarrow\boxed{r_a/r_e=2^{1/3}}.m=4πre3B*/μ0.\boxed{m=4\pi r_e^3B_*/\mu_0}.

(b) Interpretation and further calculation

𝑩+z=B*ẑ,𝑩−z=B*ẑ.\mathbf B_{+z}=B_*\hat z,\qquad\mathbf B_{-z}=B_*\hat z.𝑩equator=−B*ẑ.\boxed{\mathbf B_{\mathrm{equator}}=-B_*\hat z}.

Physical check

On the negative axial side the field points toward the dipole, but its vector still points along +z.