Maxwell's Equations — Question 9

Section 32-4 · Physics pages 5248–5249

Question 9 A current sheet produces a tangential magnetic-field jump An infinite sheet at z=0 carries surface current K = Kˆx. Vacuum lies on both sides. Symmetry gives uniform opposite magnetic fields tangent to the sheet. Kˆx above: −ˆy below: +ˆy Schematic; labels, not drawing lengths, specify the data. (a) Use a narrow rectangular Ampere loop to find B above and below the sheet. (b) Check normal-field continuity and write the vector jump condition with normal +z.
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Question 9 - Solution A current sheet produces a tangential magnetic-field jump Kˆx above: −ˆy below: +ˆy (a) Method and calculation 2Bℓ= µ0Kℓ⇒B = µ0K/2. Bz>0 = −µ0Kˆy/2, Bz<0 = +µ0Kˆy/2 . (b) Interpretation and further calculation B2z = B1z = 0, B2 −B1 = −µ0Kˆy. ˆz × (B2 −B1) = µ0K . Physical check The tangential jump encodes surface current, while the normal magnetic component remains continuous.

Question 9

A current sheet produces a tangential magnetic-field jump

An infinite sheet at z=0 carries surface current 𝑲=Kx̂\mathbf K=K\hat x. Vacuum lies on both sides. Symmetry gives uniform opposite magnetic fields tangent to the sheet.

Diagram shown in the original SVG worksheet.

  1. Use a narrow rectangular Ampere loop to find B above and below the sheet.

  2. Check normal-field continuity and write the vector jump condition with normal +z.

Question 9 - Solution

A current sheet produces a tangential magnetic-field jump

Diagram shown in the original SVG worksheet.

(a) Method and calculation

2Bℓ=μ0Kℓ⇒B=μ0K/2.2B\ell=\mu_0K\ell\Rightarrow B=\mu_0K/2.𝑩z>0=−μ0Kŷ/2,𝑩z<0=+μ0Kŷ/2.\boxed{\mathbf B_{z>0}=-\mu_0K\hat y/2,\quad\mathbf B_{z<0}=+\mu_0K\hat y/2}.

(b) Interpretation and further calculation

B2z=B1z=0,𝑩2−𝑩1=−μ0Kŷ.B_{2z}=B_{1z}=0,\quad\mathbf B_2-\mathbf B_1=-\mu_0K\hat y.ẑ×(𝑩2−𝑩1)=μ0𝑲.\boxed{\hat z\times(\mathbf B_2-\mathbf B_1)=\mu_0\mathbf K}.

Physical check

The tangential jump encodes surface current, while the normal magnetic component remains continuous.