Maxwell's Equations — Question 3

Section 32-4 · Physics pages 5236–5237

Question 3 Both curl equations determine vacuum propagation speed and field ratio Consider source-free fields E = E0 cos(kx −ωt)ˆy and B = B0 cos(kx −ωt)ˆz, with positive k and omega. +x Ey Bz out Schematic; labels, not drawing lengths, specify the data. (a) Apply Faraday law to relate amplitudes. (b) Apply the Ampere-Maxwell law to find phase speed and the amplitude ratio.
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Question 3 - Solution Both curl equations determine vacuum propagation speed and field ratio +x Ey Bz out (a) Method and calculation (∇× E)z = −kE0 sin(kx −ωt) = −∂tBz. kE0 = ωB0 . (b) Interpretation and further calculation (∇× B)y = kB0 sin(kx −ωt) = µ0ϵ0ωE0 sin(kx −ωt). ω/k = c = 1/√µ0ϵ0, E0 = cB0 . Physical check Each curl equation supplies one relation; using only one does not fix the propagation speed.

Question 3

Both curl equations determine vacuum propagation speed and field ratio

Consider source-free fields 𝑬=E0cos⁡(kx−ωt)ŷ\mathbf E=E_0\cos(kx-\omega t)\hat y and 𝑩=B0cos⁡(kx−ωt)ẑ\mathbf B=B_0\cos(kx-\omega t)\hat z, with positive k and omega.

Diagram shown in the original SVG worksheet.

  1. Apply Faraday law to relate amplitudes.

  2. Apply the Ampere-Maxwell law to find phase speed and the amplitude ratio.

Question 3 - Solution

Both curl equations determine vacuum propagation speed and field ratio

Diagram shown in the original SVG worksheet.

(a) Method and calculation

(∇×𝑬)z=−kE0sin⁡(kx−ωt)=−∂tBz.(\nabla\times\mathbf E)_z=-kE_0\sin(kx-\omega t)=-\partial_tB_z.kE0=ωB0.\boxed{kE_0=\omega B_0}.

(b) Interpretation and further calculation

(∇×𝑩)y=kB0sin⁡(kx−ωt)=μ0ϵ0ωE0sin⁡(kx−ωt).(\nabla\times\mathbf B)_y=kB_0\sin(kx-\omega t)=\mu_0\epsilon_0\omega E_0\sin(kx-\omega t).ω/k=c=1/μ0ϵ0,E0=cB0.\boxed{\omega/k=c=1/\sqrt{\mu_0\epsilon_0},\quad E_0=cB_0}.

Physical check

Each curl equation supplies one relation; using only one does not fix the propagation speed.