Displacement Current — Question 7

Section 32-3 · Physics pages 5224–5225

Question 7 Charge conservation makes the generalized current divergence-free In vacuum, local charge conservation is ∇· J = −∂tρ and Gauss law is ∇· E = ρ/ϵ0. Schematic; labels, not drawing lengths, specify the data. (a) Show that J + ϵ0∂tE has zero divergence. (b) Integrate over a fixed volume to relate net outward conduction and displacement currents.
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Question 7 - Solution Charge conservation makes the generalized current divergence-free (a) Method and calculation ∇· (J + ϵ0∂tE) = −˙ρ + ϵ0∂t(ρ/ϵ0) = 0. ∇· Jgeneralized = 0 . (b) Interpretation and further calculation I J · dA = −dQenc/dt, I ϵ0∂tE · dA = dQenc/dt. Ic,out + Id,out = 0 . Physical check Conduction current alone can converge where charge accumulates; the generalized current has no such divergence.

Question 7

Charge conservation makes the generalized current divergence-free

In vacuum, local charge conservation is ∇⋅𝑱=−∂tρ\nabla\cdot\mathbf J=-\partial_t\rho and Gauss law is ∇⋅𝑬=ρ/ϵ0\nabla\cdot\mathbf E=\rho/\epsilon_0.

Diagram shown in the original SVG worksheet.

  1. Show that 𝑱+ϵ0∂t𝑬\mathbf J+\epsilon_0\partial_t\mathbf E has zero divergence.

  2. Integrate over a fixed volume to relate net outward conduction and displacement currents.

Question 7 - Solution

Charge conservation makes the generalized current divergence-free

Diagram shown in the original SVG worksheet.

(a) Method and calculation

∇⋅(𝑱+ϵ0∂t𝑬)=−ρ̇+ϵ0∂t(ρ/ϵ0)=0.\nabla\cdot(\mathbf J+\epsilon_0\partial_t\mathbf E)=-\dot\rho+\epsilon_0\partial_t(\rho/\epsilon_0)=0.∇⋅𝑱generalized=0.\boxed{\nabla\cdot\mathbf J_{\mathrm{generalized}}=0}.

(b) Interpretation and further calculation

∮𝑱⋅d𝑨=−dQenc/dt,∮ϵ0∂t𝑬⋅d𝑨=dQenc/dt.\oint\mathbf J\cdot d\mathbf A=-dQ_{\mathrm{enc}}/dt,\quad\oint\epsilon_0\partial_t\mathbf E\cdot d\mathbf A=dQ_{\mathrm{enc}}/dt.Ic,out+Id,out=0.\boxed{I_{c,\mathrm{out}}+I_{d,\mathrm{out}}=0}.

Physical check

Conduction current alone can converge where charge accumulates; the generalized current has no such divergence.