Displacement Current — Question 5

Section 32-3 · Physics pages 5220–5221

Question 5 A dielectric separates vacuum displacement from polarization current A linear nonmagnetic dielectric of relative permittivity kappa completely fills a fixed parallel-plate capacitor. Use D = κϵ0E and P = (κ −1)ϵ0E. Free charging current is I. E(t) d I Schematic; labels, not drawing lengths, specify the data. (a) Find the vacuum displacement contribution and polarization-current contribution across the plate area. (b) Evaluate their fractions for kappa=5 and verify the total generalized current.
Show solutionHide solution
Question 5 - Solution A dielectric separates vacuum displacement from polarization current E(t) d I (a) Method and calculation I = A ˙D = κϵ0A ˙E. Id,0 = ϵ0A ˙E = I/κ . (b) Interpretation and further calculation IP = A ˙P = (κ −1)ϵ0A ˙E. κ = 5 : Id,0 = I/5, IP = 4I/5, Id,0 + IP = I . Physical check Using only the vacuum term inside a dielectric omits the current associated with changing polarization.

Question 5

A dielectric separates vacuum displacement from polarization current

A linear nonmagnetic dielectric of relative permittivity kappa completely fills a fixed parallel-plate capacitor. Use D=κϵ0ED=\kappa\epsilon_0E and P=(κ−1)ϵ0EP=(\kappa-1)\epsilon_0E. Free charging current is I.

Diagram shown in the original SVG worksheet.

  1. Find the vacuum displacement contribution and polarization-current contribution across the plate area.

  2. Evaluate their fractions for kappa=5 and verify the total generalized current.

Question 5 - Solution

A dielectric separates vacuum displacement from polarization current

Diagram shown in the original SVG worksheet.

(a) Method and calculation

I=AḊ=κϵ0AĖ.I=A\dot D=\kappa\epsilon_0A\dot E.Id,0=ϵ0AĖ=I/κ.\boxed{I_{d,0}=\epsilon_0A\dot E=I/\kappa}.

(b) Interpretation and further calculation

IP=AṖ=(κ−1)ϵ0AĖ.I_P=A\dot P=(\kappa-1)\epsilon_0A\dot E.κ=5:Id,0=I/5,IP=4I/5,Id,0+IP=I.\boxed{\kappa=5:\ I_{d,0}=I/5,\ I_P=4I/5,\ I_{d,0}+I_P=I}.

Physical check

Using only the vacuum term inside a dielectric omits the current associated with changing polarization.