Gauss' Law for Magnetic Fields — Question 10

Section 32-1 · Physics pages 5190–5191

Question 10 An axial field that weakens along a tube requires radial spreading Near the axis of a cylindrically symmetric field, assume Bz = B0(z) is independent of r and there is no azimuthal component. The radial component is finite at r=0. Use ∇· B = r−1∂r(rBr) + ∂zBz. z weakening axial field; outward Br Schematic; labels, not drawing lengths, specify the data. (a) Find Br in terms of the axial gradient. (b) For B0(z) = B∗e−z/ℓ, find Br and its direction for positive z and positive Bstar.
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Question 10 - Solution An axial field that weakens along a tube requires radial spreading z weakening axial field; outward Br (a) Method and calculation ∂r(rBr) = −rB′ 0(z) ⇒rBr = −r2B′ 0/2 + f(z). Br = −r 2B′ 0(z) since finiteness requires f = 0. (b) Interpretation and further calculation B′ 0 = −B0/ℓ. Br = rB0(z) 2ℓ > 0 (outward) . Physical check Axial weakening is accompanied by transverse flux spreading, preserving zero magnetic divergence.

Question 10

An axial field that weakens along a tube requires radial spreading

Near the axis of a cylindrically symmetric field, assume Bz=B0(z)B_z=B_0(z) is independent of r and there is no azimuthal component. The radial component is finite at r=0. Use ∇⋅𝑩=r−1∂r(rBr)+∂zBz\nabla\cdot\mathbf B=r^{-1}\partial_r(rB_r)+\partial_zB_z.

Diagram shown in the original SVG worksheet.

  1. Find Br in terms of the axial gradient.

  2. For B0(z)=B*e−z/ℓB_0(z)=B_*e^{-z/\ell}, find Br and its direction for positive z and positive Bstar.

Question 10 - Solution

An axial field that weakens along a tube requires radial spreading

Diagram shown in the original SVG worksheet.

(a) Method and calculation

∂r(rBr)=−rB0′(z)⇒rBr=−r2B0′/2+f(z).\partial_r(rB_r)=-rB_0^{\prime}(z)\Rightarrow rB_r=-r^2B_0^{\prime}/2+f(z).Br=−r2B0′(z)since finiteness requires f=0.\boxed{B_r=-\tfrac r2B_0^{\prime}(z)}\quad\text{since finiteness requires }f=0.

(b) Interpretation and further calculation

B0′=−B0/ℓ.B_0^{\prime}=-B_0/\ell.Br=rB0(z)2ℓ>0(outward).\boxed{B_r=\frac{rB_0(z)}{2\ell}>0\quad\text{(outward)}}.

Physical check

Axial weakening is accompanied by transverse flux spreading, preserving zero magnetic divergence.