Gauss' Law for Magnetic Fields — Question 2

Section 32-1 · Physics pages 5174–5175

Question 2 A tilted uniform field has cancelling fluxes through a closed cylinder A cylinder of cap area A is in uniform field B making angle theta with its axis. Both end caps and the curved side form the closed surface. B Schematic; labels, not drawing lengths, specify the data. (a) Find the two cap fluxes using outward normals. (b) Find the net curved-side flux, even though the field crosses parts of the side.
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Question 2 - Solution A tilted uniform field has cancelling fluxes through a closed cylinder B (a) Method and calculation Φtop = BA cos θ, Φbottom = −BA cos θ. Φtop + Φbottom = 0 . (b) Interpretation and further calculation Φside = −(Φtop + Φbottom). Φside = 0 as a signed integral . Physical check Local entry and exit on the curved surface cancel; the local normal field need not vanish.

Question 2

A tilted uniform field has cancelling fluxes through a closed cylinder

A cylinder of cap area A is in uniform field B making angle theta with its axis. Both end caps and the curved side form the closed surface.

Diagram shown in the original SVG worksheet.

  1. Find the two cap fluxes using outward normals.

  2. Find the net curved-side flux, even though the field crosses parts of the side.

Question 2 - Solution

A tilted uniform field has cancelling fluxes through a closed cylinder

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Φtop=BAcos⁡θ,Φbottom=−BAcos⁡θ.\Phi_{\mathrm{top}}=BA\cos\theta,\quad\Phi_{\mathrm{bottom}}=-BA\cos\theta.Φtop+Φbottom=0.\boxed{\Phi_{\mathrm{top}}+\Phi_{\mathrm{bottom}}=0}.

(b) Interpretation and further calculation

Φside=−(Φtop+Φbottom).\Phi_{\mathrm{side}}=-(\Phi_{\mathrm{top}}+\Phi_{\mathrm{bottom}}).Φside=0as a signed integral.\boxed{\Phi_{\mathrm{side}}=0\quad\text{as a signed integral}}.

Physical check

Local entry and exit on the curved surface cancel; the local normal field need not vanish.