Power in Alternating-Current Circuits — Question 10

Section 31-9 · Physics pages 5150–5151

Question 10 Maximizing resistor power by changing resistance differs from tuning resonance An ideal fixed rms voltage V drives a series impedance with adjustable positive R and fixed nonzero net reactance X. Frequency and reactive components do not change. R P |X| Schematic; labels, not drawing lengths, specify the data. (a) Find the R that maximizes real resistor power. (b) Find the maximum power and power factor at this optimum.
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Question 10 - Solution Maximizing resistor power by changing resistance differs from tuning resonance R P |X| (a) Method and calculation P(R) = V 2R R2 + X2 , dP dR = V 2 X2 −R2 (R2 + X2)2 . Roptimum = |X| . (b) Interpretation and further calculation Pmax = V 2|X| 2X2 = V 2/(2|X|). pf = R/ √ R2 + X2 = 1/ √ 2 . Physical check With reactance held nonzero, very small resistance draws mostly reactive current and dissipates little real power.

Question 10

Maximizing resistor power by changing resistance differs from tuning resonance

An ideal fixed rms voltage V drives a series impedance with adjustable positive R and fixed nonzero net reactance X. Frequency and reactive components do not change.

Diagram shown in the original SVG worksheet.

  1. Find the R that maximizes real resistor power.

  2. Find the maximum power and power factor at this optimum.

Question 10 - Solution

Maximizing resistor power by changing resistance differs from tuning resonance

Diagram shown in the original SVG worksheet.

(a) Method and calculation

P(R)=V2RR2+X2,dPdR=V2X2−R2(R2+X2)2.P(R)=\frac{V^2R}{R^2+X^2},\quad\frac{dP}{dR}=V^2\frac{X^2-R^2}{(R^2+X^2)^2}.Roptimum=|X|.\boxed{R_{\mathrm{optimum}}=|X|}.

(b) Interpretation and further calculation

Pmax=V2|X|2X2=V2/(2|X|).P_{\max}=\frac{V^2|X|}{2X^2}=V^2/(2|X|).pf=R/R2+X2=1/2.\boxed{\mathrm{pf}=R/\sqrt{R^2+X^2}=1/\sqrt2}.

Physical check

With reactance held nonzero, very small resistance draws mostly reactive current and dissipates little real power.