Power in Alternating-Current Circuits — Question 7

Section 31-9 · Physics pages 5144–5145

Question 7 Inductive and capacitive loads combine by adding signed reactive power Two parallel loads share a 200-V rms source. Load 1 has P1 = 800 W and Q1 = +600 var. Load 2 has P2 = 600 W and Q2 = −800 var. Both operate sinusoidally at the same frequency. P S Qr Schematic; labels, not drawing lengths, specify the data. (a) Find total real, reactive, and apparent power. (b) Find source current and total power factor with its leading or lagging designation.
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Question 7 - Solution Inductive and capacitive loads combine by adding signed reactive power P S Qr (a) Method and calculation P = P1 + P2 = 1400 W, Qr = Q1 + Q2 = −200 var. S = √ P 2 + Q2r = 1414.21 V A . (b) Interpretation and further calculation I = S/V = 1414.21/200 = 7.07107 A. pf = P/S = .989949 leading . Physical check Apparent powers do not generally add as scalar magnitudes; signed reactive contributions can cancel.

Question 7

Inductive and capacitive loads combine by adding signed reactive power

Two parallel loads share a 200-V rms source. Load 1 has P1=800P_1=800 W and Q1=+600Q_1=+600 var. Load 2 has P2=600P_2=600 W and Q2=−800Q_2=-800 var. Both operate sinusoidally at the same frequency.

Diagram shown in the original SVG worksheet.

  1. Find total real, reactive, and apparent power.

  2. Find source current and total power factor with its leading or lagging designation.

Question 7 - Solution

Inductive and capacitive loads combine by adding signed reactive power

Diagram shown in the original SVG worksheet.

(a) Method and calculation

P=P1+P2=1400W,Qr=Q1+Q2=−200var.P=P_1+P_2=1400\,W,\quad Q_r=Q_1+Q_2=-200\,var.S=P2+Qr2=1414.21VA.\boxed{S=\sqrt{P^2+Q_r^2}=1414.21\,VA}.

(b) Interpretation and further calculation

I=S/V=1414.21/200=7.07107A.I=S/V=1414.21/200=7.07107\,A.pf=P/S=.989949leading.\boxed{\mathrm{pf}=P/S=.989949\quad\text{leading}}.

Physical check

Apparent powers do not generally add as scalar magnitudes; signed reactive contributions can cancel.