The Series RLC Circuit — Question 2

Section 31-8 · Physics pages 5114–5115

Question 2 Three component voltmeters can reconstruct the source phase In a series RLC circuit, ideal rms meters read VR = 60.0 V, VL = 120 V, and VC = 40.0 V. R=30.0 ohms and ω = 500 radians per second. current reference V VR Schematic; labels, not drawing lengths, specify the data. (a) Find source rms voltage and current phase. (b) Infer L and C.
Show solutionHide solution
Question 2 - Solution Three component voltmeters can reconstruct the source phase current reference V VR (a) Method and calculation I = VR/R = 2.00 A, V = √ 602 + (120 −40)2. V = 100 V, ϕ = tan−1(80/60) = 53.1301◦lag . (b) Interpretation and further calculation L = VL/(ωI) = 120/(500 · 2). L = .120 H, C = I/(ωVC) = 100 µF . Physical check The component readings determine both the net reactive sign and the element values.

Question 2

Three component voltmeters can reconstruct the source phase

In a series RLC circuit, ideal rms meters read VR=60.0V_R=60.0 V, VL=120V_L=120 V, and VC=40.0V_C=40.0 V. R=30.0 ohms and ω=500\omega=500 radians per second.

Diagram shown in the original SVG worksheet.

  1. Find source rms voltage and current phase.

  2. Infer L and C.

Question 2 - Solution

Three component voltmeters can reconstruct the source phase

Diagram shown in the original SVG worksheet.

(a) Method and calculation

I=VR/R=2.00A,V=602+(120−40)2.I=V_R/R=2.00\,A,\quad V=\sqrt{60^2+(120-40)^2}.V=100V,ϕ=tan⁡−1(80/60)=53.1301∘lag.\boxed{V=100\,V,\quad\phi=\tan^{-1}(80/60)=53.1301^\circ\ \text{lag}}.

(b) Interpretation and further calculation

L=VL/(ωI)=120/(500⋅2).L=V_L/(\omega I)=120/(500\cdot2).L=.120H,C=I/(ωVC)=100μF.\boxed{L=.120\,H,\quad C=I/(\omega V_C)=100\,\mu F}.

Physical check

The component readings determine both the net reactive sign and the element values.