Three Simple Circuits — Question 5

Section 31-7 · Physics pages 5100–5101

Question 5 Equal reactances also equalize peak stored energies under equal voltage Separate ideal L and C elements are each driven by the same sinusoidal peak voltage Vp at adjustable frequency. Assume the inductor current has zero DC component. L C separate equal-voltage tests Schematic; labels, not drawing lengths, specify the data. (a) Find the frequency at which their peak currents are equal. (b) Compare their maximum stored energies at this frequency and at twice it.
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Question 5 - Solution Equal reactances also equalize peak stored energies under equal voltage L C separate equal-voltage tests (a) Method and calculation IL,p = Vp/(ωL), IC,p = ωCVp. ω∗= 1/ √ LC . (b) Interpretation and further calculation UL,max = V 2 p /(2ω2L), UC,max = CV 2 p /2. UL,max/UC,max = ω2 ∗/ω2 = 1 at ω∗; 1/4 at 2ω∗. Physical check Capacitor peak energy is set by voltage amplitude, while inductor peak energy decreases with drive frequency.

Question 5

Equal reactances also equalize peak stored energies under equal voltage

Separate ideal L and C elements are each driven by the same sinusoidal peak voltage Vp at adjustable frequency. Assume the inductor current has zero DC component.

Diagram shown in the original SVG worksheet.

  1. Find the frequency at which their peak currents are equal.

  2. Compare their maximum stored energies at this frequency and at twice it.

Question 5 - Solution

Equal reactances also equalize peak stored energies under equal voltage

Diagram shown in the original SVG worksheet.

(a) Method and calculation

IL,p=Vp/(ωL),IC,p=ωCVp.I_{L,p}=V_p/(\omega L),\quad I_{C,p}=\omega CV_p.ω*=1/LC.\boxed{\omega_*=1/\sqrt{LC}}.

(b) Interpretation and further calculation

UL,max=Vp2/(2ω2L),UC,max=CVp2/2.U_{L,\max}=V_p^2/(2\omega^2L),\quad U_{C,\max}=CV_p^2/2.UL,max/UC,max=ω*2/ω2=1atω*;1/4at2ω*.\boxed{U_{L,\max}/U_{C,\max}=\omega_*^2/\omega^2=1\ \text{at}\ \omega_*;\quad1/4\ \text{at}\ 2\omega_*}.

Physical check

Capacitor peak energy is set by voltage amplitude, while inductor peak energy decreases with drive frequency.