Forced Oscillations — Question 9

Section 31-6 · Physics pages 5088–5089

Question 9 Resonant charge amplitude measures resistance when L and C are known A driven circuit has L=.100 H and C=100 microfarads. At its natural frequency the measured steady charge amplitude is 2.00 mC with source peak 10.0 V. ∼ vs(t) R C L q i = ˙q Schematic; labels, not drawing lengths, specify the data. (a) Infer the resistance and current amplitude. (b) Find the damped natural frequency after the source is disconnected, if the circuit remains closed.
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Question 9 - Solution Resonant charge amplitude measures resistance when L and C are known ∼ vs(t) R C L q i = ˙q (a) Method and calculation ω0 = 1/ √ LC = 316.228 s−1, Q = Vp/(Rω0). R = 15.8114 Ω, Ip = ω0Q = .632456 A . (b) Interpretation and further calculation α = R/(2L) = 79.0569 s−1, ωd = √ ω2 0 −α2. ωd = 306.186 s−1 . Physical check The forced frequency equals the source frequency; after disconnection the remaining motion has the damped natural frequency.

Question 9

Resonant charge amplitude measures resistance when L and C are known

A driven circuit has L=.100 H and C=100 microfarads. At its natural frequency the measured steady charge amplitude is 2.00 mC with source peak 10.0 V.

Diagram shown in the original SVG worksheet.

  1. Infer the resistance and current amplitude.

  2. Find the damped natural frequency after the source is disconnected, if the circuit remains closed.

Question 9 - Solution

Resonant charge amplitude measures resistance when L and C are known

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ω0=1/LC=316.228s−1,Q=Vp/(Rω0).\omega_0=1/\sqrt{LC}=316.228\,s^{-1},\quad Q=V_p/(R\omega_0).R=15.8114Ω,Ip=ω0Q=.632456A.\boxed{R=15.8114\,\Omega,\quad I_p=\omega_0Q=.632456\,A}.

(b) Interpretation and further calculation

α=R/(2L)=79.0569s−1,ωd=ω02−α2.\alpha=R/(2L)=79.0569\,s^{-1},\quad\omega_d=\sqrt{\omega_0^2-\alpha^2}.ωd=306.186s−1.\boxed{\omega_d=306.186\,s^{-1}}.

Physical check

The forced frequency equals the source frequency; after disconnection the remaining motion has the damped natural frequency.