Forced Oscillations — Question 2

Section 31-6 · Physics pages 5074–5075

Question 2 The steady-state phase moves from elastic response to inertial response A series RLC circuit is driven by Vp cos ωt. Its charge amplitude is Q = Vp/ √ (1/C −Lω2)2 + (Rω)2, and charge lags the drive by delta. ∼ vs(t) R C L q i = ˙q Schematic; labels, not drawing lengths, specify the data. (a) Find low-frequency and high-frequency limits of Q and delta. (b) Find charge and current at the natural frequency ω0 = 1/ √ LC.
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Question 2 - Solution The steady-state phase moves from elastic response to inertial response ∼ vs(t) R C L q i = ˙q (a) Method and calculation ω →0 : Q →CVp, δ →0 . ω →∞: Q ∼Vp/(Lω2), δ →π . (b) Interpretation and further calculation ω = ω0 : q = Vp Rω0 sin ω0t. i = ˙q = (Vp/R) cos ω0t . Physical check At the natural frequency, current is in phase with the drive while charge lags by a quarter-cycle.

Question 2

The steady-state phase moves from elastic response to inertial response

A series RLC circuit is driven by Vpcos⁡ωtV_p\cos\omega t. Its charge amplitude is Q=Vp/(1/C−Lω2)2+(Rω)2Q=V_p/\sqrt{(1/C-L\omega^2)^2+(R\omega)^2}, and charge lags the drive by delta.

Diagram shown in the original SVG worksheet.

  1. Find low-frequency and high-frequency limits of Q and delta.

  2. Find charge and current at the natural frequency ω0=1/LC\omega_0=1/\sqrt{LC}.

Question 2 - Solution

The steady-state phase moves from elastic response to inertial response

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ω→0:Q→CVp,δ→0.\omega\to0:\quad\boxed{Q\to CV_p,\quad\delta\to0}.ω→∞:Q∼Vp/(Lω2),δ→π.\omega\to\infty:\quad\boxed{Q\sim V_p/(L\omega^2),\quad\delta\to\pi}.

(b) Interpretation and further calculation

ω=ω0:q=VpRω0sin⁡ω0t.\omega=\omega_0:\quad q=\frac{V_p}{R\omega_0}\sin\omega_0t.i=q̇=(Vp/R)cos⁡ω0t.\boxed{i=\dot q=(V_p/R)\cos\omega_0t}.

Physical check

At the natural frequency, current is in phase with the drive while charge lags by a quarter-cycle.