LC Oscillations, Quantitatively — Question 10

Section 31-3 · Physics pages 5030–5031

Question 10 Peak energy-transfer power occurs between the field-energy extrema An ideal LC oscillator starts with maximum capacitor energy U and q = Q cos ωt. ωt PC/(ωU) Schematic; labels, not drawing lengths, specify the data. (a) Derive instantaneous power flowing into the capacitor. (b) Find the largest magnitude of transfer power and the charge and current magnitudes at that instant.
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Question 10 - Solution Peak energy-transfer power occurs between the field-energy extrema ωt PC/(ωU) (a) Method and calculation PC = d dt(U cos2 ωt) = −ωU sin 2ωt. |PC|max = ωU . (b) Interpretation and further calculation | sin 2ωt| = 1 ⇒cos2 ωt = sin2 ωt = 1/2. |q| = Q/ √ 2, |i| = Imax/ √ 2 . Physical check Largest transfer power occurs at equal field energies, not when either store alone is maximum.

Question 10

Peak energy-transfer power occurs between the field-energy extrema

An ideal LC oscillator starts with maximum capacitor energy U and q=Qcos⁡ωtq=Q\cos\omega t.

Diagram shown in the original SVG worksheet.

  1. Derive instantaneous power flowing into the capacitor.

  2. Find the largest magnitude of transfer power and the charge and current magnitudes at that instant.

Question 10 - Solution

Peak energy-transfer power occurs between the field-energy extrema

Diagram shown in the original SVG worksheet.

(a) Method and calculation

PC=ddt(Ucos⁡2ωt)=−ωUsin⁡2ωt.P_C=\frac d{dt}(U\cos^2\omega t)=-\omega U\sin2\omega t.|PC|max=ωU.\boxed{|P_C|_{\max}=\omega U}.

(b) Interpretation and further calculation

|sin⁡2ωt|=1⇒cos⁡2ωt=sin⁡2ωt=1/2.|\sin2\omega t|=1\Rightarrow\cos^2\omega t=\sin^2\omega t=1/2.|q|=Q/2,|i|=Imax/2.\boxed{|q|=Q/\sqrt2,\quad|i|=I_{\max}/\sqrt2}.

Physical check

Largest transfer power occurs at equal field energies, not when either store alone is maximum.