LC Oscillations, Quantitatively — Question 7

Section 31-3 · Physics pages 5024–5025

Question 7 Current zero crossings reveal a sign ambiguity in a sampled charge An ideal LC loop has successive current zero crossings separated by .600 ms. At the first crossing q is positive. A charge sensor sampled .200 ms later reads 4.00 µC. ωt q/Q Schematic; labels, not drawing lengths, specify the data. (a) Find the period and maximum charge. (b) Find the charge at the second current zero crossing.
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Question 7 - Solution Current zero crossings reveal a sign ambiguity in a sampled charge ωt q/Q (a) Method and calculation ∆ti=0 = T/2 ⇒T = 1.200 ms . ω(.200 ms) = π/3, q = Q cos(π/3) = Q/2 ⇒Q = 8.00 µC . (b) Interpretation and further calculation q(T/2) = Q cos π. q(T/2) = −8.00 µC . Physical check Successive current zeros alternate between opposite charge extrema.

Question 7

Current zero crossings reveal a sign ambiguity in a sampled charge

An ideal LC loop has successive current zero crossings separated by .600 ms. At the first crossing q is positive. A charge sensor sampled .200 ms later reads 4.00μC4.00\,\mu C.

Diagram shown in the original SVG worksheet.

  1. Find the period and maximum charge.

  2. Find the charge at the second current zero crossing.

Question 7 - Solution

Current zero crossings reveal a sign ambiguity in a sampled charge

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Δti=0=T/2⇒T=1.200ms.\Delta t_{i=0}=T/2\Rightarrow\boxed{T=1.200\,ms}.ω(.200ms)=π/3,q=Qcos⁡(π/3)=Q/2⇒Q=8.00μC.\omega(.200\,ms)=\pi/3,\quad q=Q\cos(\pi/3)=Q/2\Rightarrow\boxed{Q=8.00\,\mu C}.

(b) Interpretation and further calculation

q(T/2)=Qcos⁡π.q(T/2)=Q\cos\pi.q(T/2)=−8.00μC.\boxed{q(T/2)=-8.00\,\mu C}.

Physical check

Successive current zeros alternate between opposite charge extrema.