LC Oscillations, Quantitatively — Question 3

Section 31-3 · Physics pages 5016–5017

Question 3 A specified signed charge selects different times on the outgoing and returning paths An ideal loop starts with q=Q and i=0, so q = Q cos ωt. Consider the first complete cycle. ωt q/Q Schematic; labels, not drawing lengths, specify the data. (a) Find both times at which q = −Q/2 and give the current signs. (b) Find the duration for which q is below -Q/2.
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Question 3 - Solution A specified signed charge selects different times on the outgoing and returning paths ωt q/Q (a) Method and calculation cos ωt = −1/2 ⇒t1 = T/3, t2 = 2T/3 . i = −ωQ sin ωt ⇒i(t1) = − √ 3Imax/2, i(t2) = + √ 3Imax/2 . (b) Interpretation and further calculation q < −Q/2 for 2π/3 < ωt < 4π/3. ∆t = T/3 . Physical check The same signed charge can belong to either direction of current.

Question 3

A specified signed charge selects different times on the outgoing and returning paths

An ideal loop starts with q=Q and i=0, so q=Qcos⁡ωtq=Q\cos\omega t. Consider the first complete cycle.

Diagram shown in the original SVG worksheet.

  1. Find both times at which q=−Q/2q=-Q/2 and give the current signs.

  2. Find the duration for which q is below -Q/2.

Question 3 - Solution

A specified signed charge selects different times on the outgoing and returning paths

Diagram shown in the original SVG worksheet.

(a) Method and calculation

cos⁡ωt=−1/2⇒t1=T/3,t2=2T/3.\cos\omega t=-1/2\Rightarrow\boxed{t_1=T/3,\quad t_2=2T/3}.i=−ωQsin⁡ωt⇒i(t1)=−3Imax/2,i(t2)=+3Imax/2.i=-\omega Q\sin\omega t\Rightarrow\boxed{i(t_1)=-\sqrt3 I_{\max}/2,\ i(t_2)=+\sqrt3 I_{\max}/2}.

(b) Interpretation and further calculation

q<−Q/2for2π/3<ωt<4π/3.q<-Q/2\quad\text{for}\quad2\pi/3<\omega t<4\pi/3.Δt=T/3.\boxed{\Delta t=T/3}.

Physical check

The same signed charge can belong to either direction of current.