The Electrical-Mechanical Analogy — Question 9

Section 31-2 · Physics pages 5008–5009

Question 9 Mutual inductance acts like a coupling of inertial coordinates Two identical lossless LC loops have positive mutual inductance 0 < M < L and equations L¨q1 + M ¨q2 + q1/C = 0 and M ¨q1 + L¨q2 + q2/C = 0. source I1(t) pickup Φ Schematic; labels, not drawing lengths, specify the data. (a) Find frequencies for equal-charge and opposite-charge modes. (b) Which mode is slower, and what happens as M approaches L from below?
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Question 9 - Solution Mutual inductance acts like a coupling of inertial coordinates source I1(t) pickup Φ (a) Method and calculation q2 = ±q1 ⇒(L ± M)¨q1 + q1/C = 0. ω+ = 1/ √ C(L + M), ω−= 1/ √ C(L −M) . (b) Interpretation and further calculation M > 0 ⇒L + M > L −M ⇒ω+ < ω−. M →L−: ω+ →1/ √ 2LC, ω−→∞. Physical check The divergent ideal limit signals a vanishing modal inductance; real parasitic elements then matter.

Question 9

Mutual inductance acts like a coupling of inertial coordinates

Two identical lossless LC loops have positive mutual inductance 0<M<L0<M<L and equations Lq̈1+Mq̈2+q1/C=0L\ddot q_1+M\ddot q_2+q_1/C=0 and Mq̈1+Lq̈2+q2/C=0M\ddot q_1+L\ddot q_2+q_2/C=0.

Diagram shown in the original SVG worksheet.

  1. Find frequencies for equal-charge and opposite-charge modes.

  2. Which mode is slower, and what happens as M approaches L from below?

Question 9 - Solution

Mutual inductance acts like a coupling of inertial coordinates

Diagram shown in the original SVG worksheet.

(a) Method and calculation

q2=±q1⇒(L±M)q̈1+q1/C=0.q_2=\pm q_1\Rightarrow(L\pm M)\ddot q_1+q_1/C=0.ω+=1/C(L+M),ω−=1/C(L−M).\boxed{\omega_+=1/\sqrt{C(L+M)},\quad\omega_-=1/\sqrt{C(L-M)}}.

(b) Interpretation and further calculation

M>0⇒L+M>L−M⇒ω+<ω−.M>0\Rightarrow L+M>L-M\Rightarrow\omega_+<\omega_-.M→L−:ω+→1/2LC,ω−→∞.\boxed{M\to L^-:\ \omega_+\to1/\sqrt{2LC},\quad\omega_-\to\infty}.

Physical check

The divergent ideal limit signals a vanishing modal inductance; real parasitic elements then matter.