The Electrical-Mechanical Analogy — Question 6

Section 31-2 · Physics pages 5002–5003

Question 6 Parallel springs correspond to series capacitors in the force-voltage analogy Two springs exert restoring force on the same mass displacement, so their stiffnesses add. Two capacitors carry the same series charge q. Ignore resistance and any capacitor offset charge. C1 C2 Schematic; labels, not drawing lengths, specify the data. (a) Show how the capacitor voltages reproduce additive spring forces. (b) For two identical capacitors C in series with L, compare frequency with a single C and with two identical parallel capacitors.
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Question 6 - Solution Parallel springs correspond to series capacitors in the force-voltage analogy C1 C2 (a) Method and calculation F = −(k1 + k2)x, v = q/C1 + q/C2. 1/Cs = 1/C1 + 1/C2 ↔keq = k1 + k2 . (b) Interpretation and further calculation Cs = C/2, Cp = 2C. ωs = √ 2 ω1, ωp = ω1/ √ 2 . Physical check The analogy follows shared variables; visually parallel mechanical elements need not correspond to parallel electrical elements.

Question 6

Parallel springs correspond to series capacitors in the force-voltage analogy

Two springs exert restoring force on the same mass displacement, so their stiffnesses add. Two capacitors carry the same series charge q. Ignore resistance and any capacitor offset charge.

Diagram shown in the original SVG worksheet.

  1. Show how the capacitor voltages reproduce additive spring forces.

  2. For two identical capacitors C in series with L, compare frequency with a single C and with two identical parallel capacitors.

Question 6 - Solution

Parallel springs correspond to series capacitors in the force-voltage analogy

Diagram shown in the original SVG worksheet.

(a) Method and calculation

F=−(k1+k2)x,v=q/C1+q/C2.F=-(k_1+k_2)x,\quad v=q/C_1+q/C_2.1/Cs=1/C1+1/C2↔keq=k1+k2.\boxed{1/C_s=1/C_1+1/C_2\ \leftrightarrow\ k_{\mathrm{eq}}=k_1+k_2}.

(b) Interpretation and further calculation

Cs=C/2,Cp=2C.C_s=C/2,\quad C_p=2C.ωs=2ω1,ωp=ω1/2.\boxed{\omega_s=\sqrt2\,\omega_1,\quad\omega_p=\omega_1/\sqrt2}.

Physical check

The analogy follows shared variables; visually parallel mechanical elements need not correspond to parallel electrical elements.