Transformers — Question 6

Section 31-10 · Physics pages 5162–5163

Question 6 Maximum transformer efficiency occurs when variable and fixed losses balance A transformer model has fixed core loss P0, copper loss kI2 s , and approximately constant secondary rms voltage Vs feeding a resistive load. Ignore all other losses. Is η Schematic; labels, not drawing lengths, specify the data. (a) Maximize η = VsIs/(VsIs + P0 + kI2 s ) over positive current. (b) Find optimal current and maximum efficiency for P0=20.0 W, k=.400 ohm, and Vs=24.0 V.
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Question 6 - Solution Maximum transformer efficiency occurs when variable and fixed losses balance Is η (a) Method and calculation η−1 = 1 + P0 VsIs + kIs Vs , d dIs η−1 = 1 Vs ( k −P0 I2s ) . Is,∗= √ P0/k, kI2 s,∗= P0 . (b) Interpretation and further calculation Is,∗= √ 20/.400 = 7.07107 A, PL,∗= 24Is,∗= 169.706 W. ηmax = 169.706 169.706 + 40 = .809256 . Physical check At very low current fixed loss dominates; at high current copper loss grows faster than useful power.

Question 6

Maximum transformer efficiency occurs when variable and fixed losses balance

A transformer model has fixed core loss P0, copper loss kIs2kI_s^2, and approximately constant secondary rms voltage Vs feeding a resistive load. Ignore all other losses.

Diagram shown in the original SVG worksheet.

  1. Maximize η=VsIs/(VsIs+P0+kIs2)\eta=V_sI_s/(V_sI_s+P_0+kI_s^2) over positive current.

  2. Find optimal current and maximum efficiency for P0=20.0 W, k=.400 ohm, and Vs=24.0 V.

Question 6 - Solution

Maximum transformer efficiency occurs when variable and fixed losses balance

Diagram shown in the original SVG worksheet.

(a) Method and calculation

η−1=1+P0VsIs+kIsVs,ddIsη−1=1Vs(k−P0Is2).\eta^{-1}=1+\frac{P_0}{V_sI_s}+\frac{kI_s}{V_s},\quad\frac d{dI_s}\eta^{-1}=\frac1{V_s}\left(k-\frac{P_0}{I_s^2}\right).Is,*=P0/k,kIs,*2=P0.\boxed{I_{s,*}=\sqrt{P_0/k},\quad kI_{s,*}^2=P_0}.

(b) Interpretation and further calculation

Is,*=20/.400=7.07107A,PL,*=24Is,*=169.706W.I_{s,*}=\sqrt{20/.400}=7.07107\,A,\quad P_{L,*}=24I_{s,*}=169.706\,W.ηmax=169.706169.706+40=.809256.\boxed{\eta_{\max}=\frac{169.706}{169.706+40}=.809256}.

Physical check

At very low current fixed loss dominates; at high current copper loss grows faster than useful power.