Self-Induction — Question 7

Section 30-7 · Physics pages 4884–4885

Question 7 Changing inductance can induce an emf even when current is held constant A linear coil has time-dependent inductance L(t) = L0(1 + αt) because its geometry changes slowly. A current source holds I constant. Ignore winding resistance and hysteresis. B ℓ N turns; cross section A slowly changing geometry Schematic; labels, not drawing lengths, specify the data. (a) Find linkage, terminal voltage and self-induced emf. (b) Find the charge-source electrical work over time T and explain why the fixed-L formula alone is insufficient.
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Question 7 - Solution Changing inductance can induce an emf even when current is held constant B ℓ N turns; cross section A slowly changing geometry (a) Method and calculation Λ = L(t)I ⇒v = ˙Λ = I ˙L = αL0I . Eself = −αL0I . (b) Interpretation and further calculation Welec = ∫T 0 vi dt = αL0I2T . d dt(Li) = L˙i + i ˙L; ˙i = 0 does not remove i ˙L. Physical check Mechanical work can also be exchanged when geometry changes; electrical work need not equal the field-energy change alone.

Question 7

Changing inductance can induce an emf even when current is held constant

A linear coil has time-dependent inductance L(t)=L0(1+αt)L(t)=L_0(1+\alpha t) because its geometry changes slowly. A current source holds I constant. Ignore winding resistance and hysteresis.

Diagram shown in the original SVG worksheet.

  1. Find linkage, terminal voltage and self-induced emf.

  2. Find the charge-source electrical work over time T and explain why the fixed-L formula alone is insufficient.

Question 7 - Solution

Changing inductance can induce an emf even when current is held constant

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Λ=L(t)I⇒v=Λ̇=IL̇=αL0I.\Lambda=L(t)I\Rightarrow\boxed{v=\dot\Lambda=I\dot L=\alpha L_0I}.ℰself=−αL0I.\boxed{\mathcal E_{\mathrm{self}}=-\alpha L_0I}.

(b) Interpretation and further calculation

Welec=∫0Tvidt=αL0I2T.W_{\mathrm{elec}}=\int_0^Tvi\,dt=\boxed{\alpha L_0I^2T}.ddt(Li)=Li̇+iL̇;i̇=0 does not remove iL̇.\frac d{dt}(Li)=L\dot i+i\dot L;\quad\dot i=0\text{ does not remove }i\dot L.

Physical check

Mechanical work can also be exchanged when geometry changes; electrical work need not equal the field-energy change alone.