Inductors and Inductance — Question 8

Section 30-6 · Physics pages 4866–4867

Question 8 Geometric scaling changes inductance differently when turns or turn density is fixed An ideal long solenoid has L = µ0N2A/ℓ. Every linear dimension is enlarged by factor s while the material permeability is unchanged. B ℓ N turns; cross section A Schematic; labels, not drawing lengths, specify the data. (a) Find L scaling when N is fixed. (b) Find L scaling when the turns per unit length n is fixed instead.
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Question 8 - Solution Geometric scaling changes inductance differently when turns or turn density is fixed B ℓ N turns; cross section A (a) Method and calculation A′ = s2A, ℓ′ = sℓ, N′ = N. L′/L = s at fixed N. (b) Interpretation and further calculation n = N/ℓfixed ⇒N′ = sN. L′/L = s3 at fixed n. Physical check The two scaling laws correspond to different winding constraints; specifying only the size change is insufficient.

Question 8

Geometric scaling changes inductance differently when turns or turn density is fixed

An ideal long solenoid has L=μ0N2A/ℓL=\mu_0N^2A/\ell. Every linear dimension is enlarged by factor s while the material permeability is unchanged.

Diagram shown in the original SVG worksheet.

  1. Find L scaling when N is fixed.

  2. Find L scaling when the turns per unit length n is fixed instead.

Question 8 - Solution

Geometric scaling changes inductance differently when turns or turn density is fixed

Diagram shown in the original SVG worksheet.

(a) Method and calculation

A′=s2A,ℓ′=sℓ,N′=N.A\prime=s^2A,\quad\ell\prime=s\ell,\quad N\prime=N.L′/L=sat fixed N.\boxed{L\prime/L=s}\quad\text{at fixed }N.

(b) Interpretation and further calculation

n=N/ℓ fixed⇒N′=sN.n=N/\ell\text{ fixed}\Rightarrow N\prime=sN.L′/L=s3at fixed n.\boxed{L\prime/L=s^3}\quad\text{at fixed }n.

Physical check

The two scaling laws correspond to different winding constraints; specifying only the size change is insufficient.