Inductors and Inductance — Question 6

Section 30-6 · Physics pages 4862–4863

Question 6 Series inductances add when their magnetic coupling is negligible Two ideal linear inductors L1 and L2 are in series, sufficiently separated that mutual induction is negligible. The same current i enters their positive voltage terminals (the passive convention). L1 L2 Schematic; labels, not drawing lengths, specify the data. (a) Derive the equivalent inductance from terminal voltages. (b) For L1=3.00 mH and L2=7.00 mH, find the total voltage when current increases at 200 A/s.
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Question 6 - Solution Series inductances add when their magnetic coupling is negligible L1 L2 (a) Method and calculation v1 = L1˙i, v2 = L2˙i, v = v1 + v2. Leq = L1 + L2 . (b) Interpretation and further calculation Leq = .00300 + .00700 = .0100 H. v = (.0100)(200) = 2.00 V . Physical check Nearby coupled coils require mutual-inductance terms; simple addition is conditional on negligible coupling.

Question 6

Series inductances add when their magnetic coupling is negligible

Two ideal linear inductors L1 and L2 are in series, sufficiently separated that mutual induction is negligible. The same current i enters their positive voltage terminals (the passive convention).

Diagram shown in the original SVG worksheet.

  1. Derive the equivalent inductance from terminal voltages.

  2. For L1=3.00 mH and L2=7.00 mH, find the total voltage when current increases at 200 A/s.

Question 6 - Solution

Series inductances add when their magnetic coupling is negligible

Diagram shown in the original SVG worksheet.

(a) Method and calculation

v1=L1i̇,v2=L2i̇,v=v1+v2.v_1=L_1\dot i,\quad v_2=L_2\dot i,\quad v=v_1+v_2.Leq=L1+L2.\boxed{L_{\mathrm{eq}}=L_1+L_2}.

(b) Interpretation and further calculation

Leq=.00300+.00700=.0100H.L_{\mathrm{eq}}=.00300+.00700=.0100\,H.v=(.0100)(200)=2.00V.\boxed{v=(.0100)(200)=2.00\,V}.

Physical check

Nearby coupled coils require mutual-inductance terms; simple addition is conditional on negligible coupling.