Induced Electric Fields — Question 9

Section 30-5 · Physics pages 4848–4849

Question 9 A closed path around a flux region has nonzero electric work without a conducting wire A prescribed changing flux has constant derivative F through a fixed closed contour C. A test charge q is carried once around C while F stays constant. No wire is present, and the test charge does not perturb the source. a r axial B(t) imaginary contour C Schematic; labels, not drawing lengths, specify the data. (a) Find electric work for one and for n signed traversals. (b) Explain why this does not contradict the zero work of a magnetic force on a moving charge.
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Question 9 - Solution A closed path around a flux region has nonzero electric work without a conducting wire a r axial B(t) imaginary contour C (a) Method and calculation I C⃗ E · d⃗ℓ= −F ⇒W1 = −qF . Wn = −nqF for n traversals in the same sense. (b) Interpretation and further calculation PB = q⃗v · (⃗v ×⃗B) = 0. PE = q⃗E ·⃗v may be nonzero . Physical check The changing-field source supplies or absorbs the energy. Faraday circulation exists in space even without a conducting loop.

Question 9

A closed path around a flux region has nonzero electric work without a conducting wire

A prescribed changing flux has constant derivative F through a fixed closed contour C. A test charge q is carried once around C while F stays constant. No wire is present, and the test charge does not perturb the source.

Diagram shown in the original SVG worksheet.

  1. Find electric work for one and for n signed traversals.

  2. Explain why this does not contradict the zero work of a magnetic force on a moving charge.

Question 9 - Solution

A closed path around a flux region has nonzero electric work without a conducting wire

Diagram shown in the original SVG worksheet.

(a) Method and calculation

∮CE→⋅dℓ→=−F⇒W1=−qF.\oint_C\vec E\cdot d\vec\ell=-F\Rightarrow\boxed{W_1=-qF}.Wn=−nqFfor n traversals in the same sense.\boxed{W_n=-nqF}\quad\text{for }n\text{ traversals in the same sense}.

(b) Interpretation and further calculation

PB=qv→⋅(v→×B→)=0.P_B=q\vec v\cdot(\vec v\times\vec B)=0.PE=qE→⋅v→ may be nonzero.\boxed{P_E=q\vec E\cdot\vec v\text{ may be nonzero}}.

Physical check

The changing-field source supplies or absorbs the energy. Faraday circulation exists in space even without a conducting loop.