Induced Electric Fields — Question 1

Section 30-5 · Physics pages 4832–4833

Question 1 A changing cylindrical field induces an electric field beyond the magnetic-field region An axially symmetric field B(t)ˆz is uniform for r<a and zero for r>a. No electrostatic field is added. Let ˙B = β > 0 and positive azimuth be counterclockwise viewed from +z. a r axial B(t) Schematic; labels, not drawing lengths, specify the data. (a) Find the azimuthal electric field inside and outside. (b) Find its largest magnitude and evaluate it for a=.0400 m and beta=3.00 T/s.
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Question 1 - Solution A changing cylindrical field induces an electric field beyond the magnetic-field region a r axial B(t) (a) Method and calculation 2πrEϕ = −d dt(πr2B) ⇒Eϕ = −βr/2 (r < a) . 2πrEϕ = −πa2β ⇒Eϕ = −βa2/(2r) (r > a) . (b) Interpretation and further calculation |E| rises inside and falls outside ⇒rmax = a. |E|max = βa/2 = .0600 V/m . Physical check Zero local magnetic field outside the cylinder does not imply zero induced electric field there.

Question 1

A changing cylindrical field induces an electric field beyond the magnetic-field region

An axially symmetric field B(t)ẑB(t)\hat z is uniform for r<a and zero for r>a. No electrostatic field is added. Let Ḃ=β>0\dot B=\beta>0 and positive azimuth be counterclockwise viewed from +z.

Diagram shown in the original SVG worksheet.

  1. Find the azimuthal electric field inside and outside.

  2. Find its largest magnitude and evaluate it for a=.0400 m and beta=3.00 T/s.

Question 1 - Solution

A changing cylindrical field induces an electric field beyond the magnetic-field region

Diagram shown in the original SVG worksheet.

(a) Method and calculation

2πrEϕ=−ddt(πr2B)⇒Eϕ=−βr/2(r<a).2\pi rE_\phi=-\frac d{dt}(\pi r^2B)\Rightarrow\boxed{E_\phi=-\beta r/2\quad(r<a)}.2πrEϕ=−πa2β⇒Eϕ=−βa2/(2r)(r>a).2\pi rE_\phi=-\pi a^2\beta\Rightarrow\boxed{E_\phi=-\beta a^2/(2r)\quad(r>a)}.

(b) Interpretation and further calculation

|E| rises inside and falls outside⇒rmax=a.|E|\text{ rises inside and falls outside}\Rightarrow r_{\max}=a.|E|max=βa/2=.0600V/m.\boxed{|E|_{\max}=\beta a/2=.0600\,\mathrm{V/m}}.

Physical check

Zero local magnetic field outside the cylinder does not imply zero induced electric field there.