Induction and Energy Transfers — Question 9

Section 30-4 · Physics pages 4828–4829

Question 9 A rotating annular conductor generates radial emf and an opposing torque An annular conducting disk rotates about +z at angular speed omega in field Bˆz. Sliding contacts at radii a and b, with b>a, connect a load of resistance R. Ignore contact and disk resistance and self-inductance. ω a b Bˆz; radial contacts Schematic; labels, not drawing lengths, specify the data. (a) Find outer-minus-inner emf and load current. (b) Find the required drive torque from power balance.
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Question 9 - Solution A rotating annular conductor generates radial emf and an opposing torque ω a b Bˆz; radial contacts (a) Method and calculation⃗ v ×⃗B = ωrBˆr, E = ∫b a ωBr dr = Bω 2 (b2 −a2). i = Bω(b2 −a2) 2R . (b) Interpretation and further calculation τdriveω = Ei = i2R. τdrive = B2ω(b2 −a2)2 4R . Physical check The outer contact is positive for the stated rotation and field; the drive must replace the electrical power delivered to the load.

Question 9

A rotating annular conductor generates radial emf and an opposing torque

An annular conducting disk rotates about +z at angular speed omega in field BẑB\hat z. Sliding contacts at radii a and b, with b>a, connect a load of resistance R. Ignore contact and disk resistance and self-inductance.

Diagram shown in the original SVG worksheet.

  1. Find outer-minus-inner emf and load current.

  2. Find the required drive torque from power balance.

Question 9 - Solution

A rotating annular conductor generates radial emf and an opposing torque

Diagram shown in the original SVG worksheet.

(a) Method and calculation

v→×B→=ωrBr̂,ℰ=∫abωBrdr=Bω2(b2−a2).\vec v\times\vec B=\omega rB\hat r,\quad\mathcal E=\int_a^b\omega Br\,dr=\frac{B\omega}{2}(b^2-a^2).i=Bω(b2−a2)2R.\boxed{i=\frac{B\omega(b^2-a^2)}{2R}}.

(b) Interpretation and further calculation

τdriveω=ℰi=i2R.\tau_{\mathrm{drive}}\omega=\mathcal Ei=i^2R.τdrive=B2ω(b2−a2)24R.\boxed{\tau_{\mathrm{drive}}=\frac{B^2\omega(b^2-a^2)^2}{4R}}.

Physical check

The outer contact is positive for the stated rotation and field; the drive must replace the electrical power delivered to the load.