Induction and Energy Transfers — Question 3

Section 30-4 · Physics pages 4816–4817

Question 3 A falling conducting rod reaches a terminal speed set by electrical resistance A horizontal rod of mass m slides downward on vertical rails in a perpendicular field B. A resistor R closes the rails above it. Rail spacing is ell. Start from rest; neglect friction and inductance. v, g R ⊗B Schematic; labels, not drawing lengths, specify the data. (a) Find terminal speed and the velocity as a function of time. (b) Find the current and heating rate at terminal speed.
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Question 3 - Solution A falling conducting rod reaches a terminal speed set by electrical resistance v, g R ⊗B (a) Method and calculation m˙v = mg −B2ℓ2 R v, vT = mgR B2ℓ2 . v(t) = vT (1 −e−t/τ), τ = mR/(B2ℓ2) . (b) Interpretation and further calculation iT = BℓvT /R = mg/(Bℓ) . PR = i2 T R = mgvT . Physical check At terminal speed, gravitational potential energy is converted to heat without further increase in kinetic energy.

Question 3

A falling conducting rod reaches a terminal speed set by electrical resistance

A horizontal rod of mass m slides downward on vertical rails in a perpendicular field B. A resistor R closes the rails above it. Rail spacing is ell. Start from rest; neglect friction and inductance.

Diagram shown in the original SVG worksheet.

  1. Find terminal speed and the velocity as a function of time.

  2. Find the current and heating rate at terminal speed.

Question 3 - Solution

A falling conducting rod reaches a terminal speed set by electrical resistance

Diagram shown in the original SVG worksheet.

(a) Method and calculation

mv̇=mg−B2ℓ2Rv,vT=mgRB2ℓ2.m\dot v=mg-\frac{B^2\ell^2}{R}v,\quad\boxed{v_T=\frac{mgR}{B^2\ell^2}}.v(t)=vT(1−e−t/τ),τ=mR/(B2ℓ2).\boxed{v(t)=v_T(1-e^{-t/\tau}),\quad\tau=mR/(B^2\ell^2)}.

(b) Interpretation and further calculation

iT=BℓvT/R=mg/(Bℓ).i_T=B\ell v_T/R=\boxed{mg/(B\ell)}.PR=iT2R=mgvT.\boxed{P_R=i_T^2R=mgv_T}.

Physical check

At terminal speed, gravitational potential energy is converted to heat without further increase in kinetic energy.