Lenz's Law — Question 8

Section 30-3 · Physics pages 4806–4807

Question 8 Coplanar separated coils can induce currents with the same circulation sense Two small coils lie far apart in the same xy plane. The source moment is along +z and increases in magnitude. At the pickup, the source dipole field is along -z. Choose pickup normal +z and use its calibrated flux Φ2 = −kI1, k positive. Its resistance is R. ⊙µ1 ⊗B1 source pickup Schematic; labels, not drawing lengths, specify the data. (a) Find pickup current during increasing positive I1. (b) Compare with a coaxial pickup on the positive z axis, whose calibration is Φ2 = +kI1.
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Question 8 - Solution Coplanar separated coils can induce currents with the same circulation sense ⊙µ1 ⊗B1 source pickup (a) Method and calculation Ecoplanar = +k ˙I1, icoplanar = +k ˙I1/R . ˙I1 > 0 :⃗ µ2 ∥+ˆz, the same sense as the source. (b) Interpretation and further calculation Ecoaxial = −k ˙I1, icoaxial = −k ˙I1/R .⃗ µ2 ∥−ˆz for increasing positive source current. Physical check Lenz law opposes the local flux change; it does not require every induced loop to oppose the source loop magnetic moment.

Question 8

Coplanar separated coils can induce currents with the same circulation sense

Two small coils lie far apart in the same xy plane. The source moment is along +z and increases in magnitude. At the pickup, the source dipole field is along -z. Choose pickup normal +z and use its calibrated flux Φ2=−kI1\Phi_2=-kI_1, k positive. Its resistance is R.

Diagram shown in the original SVG worksheet.

  1. Find pickup current during increasing positive I1.

  2. Compare with a coaxial pickup on the positive z axis, whose calibration is Φ2=+kI1\Phi_2=+kI_1.

Question 8 - Solution

Coplanar separated coils can induce currents with the same circulation sense

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ℰcoplanar=+kİ1,icoplanar=+kİ1/R.\mathcal E_{\mathrm{coplanar}}=+k\dot I_1,\quad\boxed{i_{\mathrm{coplanar}}=+k\dot I_1/R}.İ1>0:μ→2∥+ẑ, the same sense as the source.\dot I_1>0:\quad\vec\mu_2\parallel+\hat z\text{, the same sense as the source}.

(b) Interpretation and further calculation

ℰcoaxial=−kİ1,icoaxial=−kİ1/R.\mathcal E_{\mathrm{coaxial}}=-k\dot I_1,\quad\boxed{i_{\mathrm{coaxial}}=-k\dot I_1/R}.μ→2∥−ẑfor increasing positive source current.\vec\mu_2\parallel-\hat z\quad\text{for increasing positive source current}.

Physical check

Lenz law opposes the local flux change; it does not require every induced loop to oppose the source loop magnetic moment.