Lenz's Law — Question 5

Section 30-3 · Physics pages 4800–4801

Question 5 A nearby loop is repelled by a rising source current and attracted by a falling one A rectangular resistive loop lies to the right of a long vertical wire carrying positive current I upward. Choose out-of-page loop normal. Its external flux is Φ = −kI, with k positive. Ignore self-inductance and hold geometry fixed while determining the response. I ⊗B Schematic; labels, not drawing lengths, specify the data. (a) Find the induced current sense when I increases and when it decreases. (b) Use the near side of the loop to determine the dominant force toward or away from the wire.
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Question 5 - Solution A nearby loop is repelled by a rising source current and attracted by a falling one I ⊗B (a) Method and calculation E = −˙Φ = k ˙I, i = k ˙I/R. ˙I > 0 : i > 0 (CCW); ˙I < 0 : i < 0 (CW). (b) Interpretation and further calculation CCW near-side current is downward, opposite the wire ⇒repulsion . CW near-side current is upward, parallel to the wire ⇒attraction . Physical check The nearer parallel segment dominates because the source field decreases with distance.

Question 5

A nearby loop is repelled by a rising source current and attracted by a falling one

A rectangular resistive loop lies to the right of a long vertical wire carrying positive current I upward. Choose out-of-page loop normal. Its external flux is Φ=−kI\Phi=-kI, with k positive. Ignore self-inductance and hold geometry fixed while determining the response.

Diagram shown in the original SVG worksheet.

  1. Find the induced current sense when I increases and when it decreases.

  2. Use the near side of the loop to determine the dominant force toward or away from the wire.

Question 5 - Solution

A nearby loop is repelled by a rising source current and attracted by a falling one

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ℰ=−Φ̇=kİ,i=kİ/R.\mathcal E=-\dot\Phi=k\dot I,\quad i=k\dot I/R.İ>0:i>0 (CCW);İ<0:i<0 (CW).\dot I>0:\ i>0\text{ (CCW)};\quad\dot I<0:\ i<0\text{ (CW)}.

(b) Interpretation and further calculation

CCW near-side current is downward, opposite the wire⇒repulsion.\text{CCW near-side current is downward, opposite the wire}\Rightarrow\boxed{\text{repulsion}}.CW near-side current is upward, parallel to the wire⇒attraction.\text{CW near-side current is upward, parallel to the wire}\Rightarrow\boxed{\text{attraction}}.

Physical check

The nearer parallel segment dominates because the source field decreases with distance.