Faraday's Law of Induction — Question 3

Section 30-2 · Physics pages 4776–4777

Question 3 Rotation creates an alternating emf even when the magnetic field is steady A coil of N turns and area A rotates in uniform B so its normal makes angle θ = ωt with the field. The resistive load is R; ignore inductance and keep angular speed constant. t E Schematic; labels, not drawing lengths, specify the data. (a) Find emf and its root-mean-square value over one rotation. (b) Find the average load power and identify the phase relation between flux and emf.
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Question 3 - Solution Rotation creates an alternating emf even when the magnetic field is steady t E (a) Method and calculation Λ = NBA cos ωt ⇒E = NBAω sin ωt . Erms = √ 1 T ∫T 0 E2dt = NBAω √ 2 . (b) Interpretation and further calculation ⟨P⟩= (NBAω)2 2R . Λ maximal at ωt = 0; E maximal at ωt = π/2. Physical check Maximum flux is not maximum emf; emf depends on the rate of change of flux.

Question 3

Rotation creates an alternating emf even when the magnetic field is steady

A coil of N turns and area A rotates in uniform B so its normal makes angle θ=ωt\theta=\omega t with the field. The resistive load is R; ignore inductance and keep angular speed constant.

Diagram shown in the original SVG worksheet.

  1. Find emf and its root-mean-square value over one rotation.

  2. Find the average load power and identify the phase relation between flux and emf.

Question 3 - Solution

Rotation creates an alternating emf even when the magnetic field is steady

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Λ=NBAcos⁡ωt⇒ℰ=NBAωsin⁡ωt.\Lambda=NBA\cos\omega t\Rightarrow\boxed{\mathcal E=NBA\omega\sin\omega t}.ℰrms=1T∫0Tℰ2dt=NBAω2.\mathcal E_{\mathrm{rms}}=\sqrt{\frac1T\int_0^T\mathcal E^2dt}=\frac{NBA\omega}{\sqrt2}.

(b) Interpretation and further calculation

⟨P⟩=(NBAω)22R.\boxed{\langle P\rangle=\frac{(NBA\omega)^2}{2R}}.Λ maximal at ωt=0;ℰ maximal at ωt=π/2.\Lambda\text{ maximal at }\omega t=0;\quad\mathcal E\text{ maximal at }\omega t=\pi/2.

Physical check

Maximum flux is not maximum emf; emf depends on the rate of change of flux.