A Current-Carrying Coil as a Magnetic Dipole — Question 2

Section 29-5 · Physics pages 4734–4735

Question 2 A zero axial component of a dipole field does not mean a zero magnetic field A small coil at the origin has moment µˆz. At distances large compared with its size, use⃗ B = µ0[3(⃗µ · ˆr)ˆr −⃗µ]/(4πr3). The observation point has polar angle theta from +z; define C = µ0µ/(4πr3). Use vacuum permeability µ0 ≃4π × 10−7 T m/A where numerical values are needed. z,⃗µ ρ⃗ r P θ Schematic; labels, not drawing lengths, specify the data. (a) Find the axial component Bz and cylindrical radial component Brho. (b) In the upper half-space, find the angle at which Bz vanishes and the total field there.
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Question 2 - Solution A zero axial component of a dipole field does not mean a zero magnetic field z,⃗µ ρ⃗ r P θ (a) Method and calculation ˆr = sin θˆρ + cos θˆz,⃗ µ · ˆr = µ cos θ. Bz = C(3 cos2 θ −1), Bρ = 3C sin θ cos θ . (b) Interpretation and further calculation Bz = 0 ⇒θ = cos−1(1/ √ 3) = 54.7356◦. Bρ = 3C √ 2/3/ √ 3 = √ 2C ,⃗ B = √ 2C ˆρ̸ = 0. Physical check A component null depends on the measurement axis. The dipole field magnitude is nonzero at every finite radius away from the source in this ideal point-dipole model.

Question 2

A zero axial component of a dipole field does not mean a zero magnetic field

A small coil at the origin has moment μẑ\mu\hat z. At distances large compared with its size, use B→=μ0[3(μ→⋅r̂)r̂−μ→]/(4πr3)\vec B=\mu_0[3(\vec\mu\cdot\hat r)\hat r-\vec\mu]/(4\pi r^3). The observation point has polar angle theta from +z; define C=μ0μ/(4πr3)C=\mu_0\mu/(4\pi r^3). Use vacuum permeability μ0≃4π×10−7Tm/A\mu_0\simeq4\pi\times10^{-7}\,\mathrm{T\,m/A} where numerical values are needed.

Diagram shown in the original SVG worksheet.

  1. Find the axial component Bz and cylindrical radial component Brho.

  2. In the upper half-space, find the angle at which Bz vanishes and the total field there.

Question 2 - Solution

A zero axial component of a dipole field does not mean a zero magnetic field

Diagram shown in the original SVG worksheet.

(a) Method and calculation

r̂=sin⁡θρ̂+cos⁡θẑ,μ→⋅r̂=μcos⁡θ.\hat r=\sin\theta\hat\rho+\cos\theta\hat z,\quad\vec\mu\cdot\hat r=\mu\cos\theta.Bz=C(3cos⁡2θ−1),Bρ=3Csin⁡θcos⁡θ.\boxed{B_z=C(3\cos^2\theta-1),\quad B_\rho=3C\sin\theta\cos\theta}.

(b) Interpretation and further calculation

Bz=0⇒θ=cos⁡−1(1/3)=54.7356∘.B_z=0\Rightarrow\boxed{\theta=\cos^{-1}(1/\sqrt3)=54.7356^\circ}.Bρ=3C2/3/3=2C,B→=2Cρ̂≠0.B_\rho=3C\sqrt{2/3}/\sqrt3=\boxed{\sqrt2C},\quad\vec B=\sqrt2C\hat\rho\ne0.

Physical check

A component null depends on the measurement axis. The dipole field magnitude is nonzero at every finite radius away from the source in this ideal point-dipole model.