Solenoids and Toroids — Question 9

Section 29-4 · Physics pages 4728–4729

Question 9 A solenoid current can be chosen from the required helical-orbit clearance A long air-core solenoid has turn density n=800 per metre and clear bore radius a=.0200 m. A nonrelativistic positive ion has mass m = 4.00 × 10−26 kg, charge q = 1.60 × 10−19 C and transverse speed v⊥= 2.00 × 104 m/s. Its helical guiding center is on the axis. Use vacuum permeability µ0 ≃4π × 10−7 T m/A where numerical values are needed. z ℓ N turns, current I guiding center on the axis Schematic; labels, not drawing lengths, specify the data. (a) Find the minimum solenoid current for the orbit radius to be no greater than a. (b) At this limiting current, find the axial pitch for v∥= 3.00 × 104 m/s.
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Question 9 - Solution A solenoid current can be chosen from the required helical-orbit clearance z ℓ N turns, current I guiding center on the axis (a) Method and calculation rL = mv⊥ qB ≤a, B = µ0nI ⇒I ≥mv⊥ qµ0na. Bmin = .250 T, Imin = 248.680 A . (b) Interpretation and further calculation T = 2πm qBmin = 2π a v⊥ = 6.28319 µs. p = v∥T = .188496 m . Physical check The guiding-center condition matters: injection directly on the axis with transverse velocity would place the orbit center offaxis and require a different clearance condition.

Question 9

A solenoid current can be chosen from the required helical-orbit clearance

A long air-core solenoid has turn density n=800 per metre and clear bore radius a=.0200 m. A nonrelativistic positive ion has mass m=4.00×10−26m=4.00\times10^{-26} kg, charge q=1.60×10−19q=1.60\times10^{-19} C and transverse speed v⟂=2.00×104v_\perp=2.00\times10^4 m/s. Its helical guiding center is on the axis. Use vacuum permeability μ0≃4π×10−7Tm/A\mu_0\simeq4\pi\times10^{-7}\,\mathrm{T\,m/A} where numerical values are needed.

Diagram shown in the original SVG worksheet.

  1. Find the minimum solenoid current for the orbit radius to be no greater than a.

  2. At this limiting current, find the axial pitch for v∥=3.00×104v_\parallel=3.00\times10^4 m/s.

Question 9 - Solution

A solenoid current can be chosen from the required helical-orbit clearance

Diagram shown in the original SVG worksheet.

(a) Method and calculation

rL=mv⟂qB≤a,B=μ0nI⇒I≥mv⟂qμ0na.r_L=\frac{mv_\perp}{qB}\le a,\quad B=\mu_0nI\Rightarrow I\ge\frac{mv_\perp}{q\mu_0na}.Bmin=.250T,Imin=248.680A.B_{\min}=.250\,\mathrm T,\quad\boxed{I_{\min}=248.680\,\mathrm A}.

(b) Interpretation and further calculation

T=2πmqBmin=2πav⟂=6.28319μs.T=\frac{2\pi m}{qB_{\min}}=2\pi\frac{a}{v_\perp}=6.28319\,\mu\mathrm s.p=v∥T=.188496m.p=v_\parallel T=\boxed{.188496\,\mathrm m}.

Physical check

The guiding-center condition matters: injection directly on the axis with transverse velocity would place the orbit center off axis and require a different clearance condition.