Solenoids and Toroids — Question 5

Section 29-4 · Physics pages 4720–4721

Question 5 A fixed copper volume and heating budget remove the apparent advantage of more turns A long thin solenoid has fixed radius R, length ell, copper resistivity rho and copper volume Vc. It is wound with N turns; ignore lead length and insulation volume. The wire cross section is adjusted as N changes. The allowed steady resistive power is P. Use vacuum permeability µ0 ≃4π × 10−7 T m/A where numerical values are needed. z ℓ N turns, current I Schematic; labels, not drawing lengths, specify the data. (a) Derive the wire resistance and the current allowed by P. (b) Show how the maximum ideal center field depends on N and explain the tradeoffin wire gauge.
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Question 5 - Solution A fixed copper volume and heating budget remove the apparent advantage of more turns z ℓ N turns, current I (a) Method and calculation Lw = 2πRN, Aw = Vc Lw , R = ρLw Aw = ρ(2πRN)2 Vc . I = √ P/R = 1 2πRN √ PVc/ρ . (b) Interpretation and further calculation B = µ0NI ℓ = µ0 2πRℓ √ PVc ρ . N →2N : Aw →Aw/2, R →4R, I →I/2, B →B. Physical check The N independence assumes unchanged material resistivity, copper volume and permitted power; it does not include thermal or packing changes.

Question 5

A fixed copper volume and heating budget remove the apparent advantage of more turns

A long thin solenoid has fixed radius R, length ell, copper resistivity rho and copper volume Vc. It is wound with N turns; ignore lead length and insulation volume. The wire cross section is adjusted as N changes. The allowed steady resistive power is P. Use vacuum permeability μ0≃4π×10−7Tm/A\mu_0\simeq4\pi\times10^{-7}\,\mathrm{T\,m/A} where numerical values are needed.

Diagram shown in the original SVG worksheet.

  1. Derive the wire resistance and the current allowed by P.

  2. Show how the maximum ideal center field depends on N and explain the tradeoff in wire gauge.

Question 5 - Solution

A fixed copper volume and heating budget remove the apparent advantage of more turns

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Lw=2πRN,Aw=VcLw,ℛ=ρLwAw=ρ(2πRN)2Vc.L_w=2\pi RN,\quad A_w=\frac{V_c}{L_w},\quad\mathcal R=\rho\frac{L_w}{A_w}=\frac{\rho(2\pi RN)^2}{V_c}.I=P/ℛ=12πRNPVc/ρ.\boxed{I=\sqrt{P/\mathcal R}=\frac1{2\pi RN}\sqrt{PV_c/\rho}}.

(b) Interpretation and further calculation

B=μ0NIℓ=μ02πRℓPVcρ.B=\frac{\mu_0NI}{\ell}=\boxed{\frac{\mu_0}{2\pi R\ell}\sqrt{\frac{PV_c}{\rho}}}.N→2N:Aw→Aw/2,ℛ→4ℛ,I→I/2,B→B.N\to2N:\quad A_w\to A_w/2,\ \mathcal R\to4\mathcal R,\ I\to I/2,\ B\to B.

Physical check

The N independence assumes unchanged material resistivity, copper volume and permitted power; it does not include thermal or packing changes.