Solenoids and Toroids — Question 1

Section 29-4 · Physics pages 4712–4713

Question 1 Stretching a long solenoid changes its field through the turn density A tightly wound air-core solenoid has N=1200 turns uniformly distributed over length ℓ= .600 m. Its radius is much smaller than its length and its current is I=.800 A. Neglect end effects at the center. Use vacuum permeability µ0 ≃4π × 10−7 T m/A where numerical values are needed. z ℓ N turns, current I Schematic; labels, not drawing lengths, specify the data. (a) Derive the interior field from an Ampère rectangle and evaluate it. (b) The solenoid is stretched to 1.50 times its length with N fixed. Find the field at fixed current and the current required to restore the initial field.
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Question 1 - Solution Stretching a long solenoid changes its field through the turn density z ℓ N turns, current I (a) Method and calculation BL = µ0(nL)I, n = N/ℓ⇒B = µ0NI/ℓ. B = (4π × 10−7)(1200)(.800)/.600 = 2.01062 mT . (b) Interpretation and further calculation B′/B = (N/1.50ℓ)/(N/ℓ) = 2/3 ⇒B′ = 1.34041 mT. I′ = 1.50I = 1.20 A restores nI. Physical check The radius does not enter the ideal long-solenoid result, but it still controls whether the end-effect approximation is valid.

Question 1

Stretching a long solenoid changes its field through the turn density

A tightly wound air-core solenoid has N=1200 turns uniformly distributed over length ℓ=.600\ell=.600 m. Its radius is much smaller than its length and its current is I=.800 A. Neglect end effects at the center. Use vacuum permeability μ0≃4π×10−7Tm/A\mu_0\simeq4\pi\times10^{-7}\,\mathrm{T\,m/A} where numerical values are needed.

Diagram shown in the original SVG worksheet.

  1. Derive the interior field from an Ampère rectangle and evaluate it.

  2. The solenoid is stretched to 1.50 times its length with N fixed. Find the field at fixed current and the current required to restore the initial field.

Question 1 - Solution

Stretching a long solenoid changes its field through the turn density

Diagram shown in the original SVG worksheet.

(a) Method and calculation

BL=μ0(nL)I,n=N/ℓ⇒B=μ0NI/ℓ.B L=\mu_0(nL)I,\quad n=N/\ell\Rightarrow\boxed{B=\mu_0NI/\ell}.B=(4π×10−7)(1200)(.800)/.600=2.01062mT.B=(4\pi\times10^{-7})(1200)(.800)/.600=\boxed{2.01062\,\mathrm{mT}}.

(b) Interpretation and further calculation

B′/B=(N/1.50ℓ)/(N/ℓ)=2/3⇒B′=1.34041mT.B\prime/B=(N/1.50\ell)/(N/\ell)=2/3\Rightarrow B\prime=1.34041\,\mathrm{mT}.I′=1.50I=1.20Arestores nI.\boxed{I\prime=1.50I=1.20\,\mathrm A}\quad\text{restores }nI.

Physical check

The radius does not enter the ideal long-solenoid result, but it still controls whether the end-effect approximation is valid.