The Magnetic Dipole Moment — Question 8

Section 28-9 · Physics pages 4646–4647

Question 8 A gyroscopic magnetic moment precesses without changing its angle to a uniform field A rapidly spinning dipole obeys the supplied relation⃗µ = γ⃗L, with constant signed gyromagnetic ratio gamma. Its only torque is⃗µ ×⃗B in uniform B. Treat L as classical angular momentum.⃗ B⃗ L θ Schematic; labels, not drawing lengths, specify the data. (a) Write the angular-momentum equation as a precession law and find the angular-velocity vector. (b) Show that the magnitude of L and its angle to B remain constant. Give the precession period.
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Question 8 - Solution A gyroscopic magnetic moment precesses without changing its angle to a uniform field⃗ B⃗ L θ (a) Method and calculation d⃗L dt = γ⃗L ×⃗B = (−γ⃗B) ×⃗L.⃗ Ω= −γ⃗B. (b) Interpretation and further calculation d dtL2 = 2⃗L · ˙⃗L = 0, d dt(⃗L ·⃗B) = 0. T = 2π |γ|B , cos θ =⃗L ·⃗B LB = constant. Physical check The torque changes the direction of a gyroscopic angular momentum, whereas damping would be needed to drive alignment.

Question 8

A gyroscopic magnetic moment precesses without changing its angle to a uniform field

A rapidly spinning dipole obeys the supplied relation μ→=γL→\vec\mu=\gamma\vec L, with constant signed gyromagnetic ratio gamma. Its only torque is μ→×B→\vec\mu\times\vec B in uniform B. Treat L as classical angular momentum.

Diagram shown in the original SVG worksheet.

  1. Write the angular-momentum equation as a precession law and find the angular-velocity vector.

  2. Show that the magnitude of L and its angle to B remain constant. Give the precession period.

Question 8 - Solution

A gyroscopic magnetic moment precesses without changing its angle to a uniform field

Diagram shown in the original SVG worksheet.

(a) Method and calculation

dL→dt=γL→×B→=(−γB→)×L→.\frac{d\vec L}{dt}=\gamma\vec L\times\vec B=(-\gamma\vec B)\times\vec L.Ω→=−γB→.\vec\Omega=-\gamma\vec B.

(b) Interpretation and further calculation

ddtL2=2L→⋅L→̇=0,ddt(L→⋅B→)=0.\frac d{dt}L^2=2\vec L\cdot\dot{\vec L}=0,\quad\frac d{dt}(\vec L\cdot\vec B)=0.T=2π|γ|B,cos⁡θ=L→⋅B→LB=constant.T=\frac{2\pi}{|\gamma|B},\quad\cos\theta=\frac{\vec L\cdot\vec B}{LB}=\text{constant}.

Physical check

The torque changes the direction of a gyroscopic angular momentum, whereas damping would be needed to drive alignment.