The Magnetic Dipole Moment — Question 5

Section 28-9 · Physics pages 4640–4641

Question 5 Rigidly combined loops add their moments as vectors in a uniform field Two small loops are rigidly attached, with magnetic moments µˆx and µˆy. A uniform field Bˆz acts on both. Mutual interaction is independent of the rigid assembly orientation and may be omitted. x y⃗ µ1⃗ µ2⃗ B = Bˆz Schematic; labels, not drawing lengths, specify the data. (a) Find the total moment, torque and external-field potential energy. (b) If the second loop is repositioned and fixed so its moment is −µˆx, find the new total torque and external-field energy. State the scope of this cancellation.
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Question 5 - Solution Rigidly combined loops add their moments as vectors in a uniform field x y⃗ µ1⃗ µ2⃗ B = Bˆz (a) Method and calculation⃗ µtotal = µ(ˆx + ˆy), |⃗µtotal| = √ 2µ.⃗ τ = µB(ˆx −ˆy), U = −⃗µtotal · Bˆz = 0. (b) Interpretation and further calculation⃗ µtotal′ = µˆx −µˆx = 0.⃗ τ′ = 0, U′ = 0 for the uniform external field. Individual loops can still experience opposing torques and internal mechanical stresses. Physical check A vanishing total dipole moment removes the uniform-field dipole coupling; it does not remove all internal forces or all possible gradient effects.

Question 5

Rigidly combined loops add their moments as vectors in a uniform field

Two small loops are rigidly attached, with magnetic moments μx̂\mu\hat x and μŷ\mu\hat y. A uniform field BẑB\hat z acts on both. Mutual interaction is independent of the rigid assembly orientation and may be omitted.

Diagram shown in the original SVG worksheet.

  1. Find the total moment, torque and external-field potential energy.

  2. If the second loop is repositioned and fixed so its moment is −μx̂-\mu\hat x, find the new total torque and external-field energy. State the scope of this cancellation.

Question 5 - Solution

Rigidly combined loops add their moments as vectors in a uniform field

Diagram shown in the original SVG worksheet.

(a) Method and calculation

μ→total=μ(x̂+ŷ),|μ→total|=2μ.\vec\mu_{\mathrm{total}}=\mu(\hat x+\hat y),\quad|\vec\mu_{\mathrm{total}}|=\sqrt2\mu.τ→=μB(x̂−ŷ),U=−μ→total⋅Bẑ=0.\vec\tau=\mu B(\hat x-\hat y),\quad U=-\vec\mu_{\mathrm{total}}\cdot B\hat z=0.

(b) Interpretation and further calculation

μ→total′=μx̂−μx̂=0.\vec\mu_{\mathrm{total}}\prime=\mu\hat x-\mu\hat x=0.τ→′=0,U′=0for the uniform external field.\vec\tau\prime=0,\quad U\prime=0\quad\text{for the uniform external field}.Individual loops can still experience opposing torques and internal mechanical stresses.

Physical check

A vanishing total dipole moment removes the uniform-field dipole coupling; it does not remove all internal forces or all possible gradient effects.