The Magnetic Dipole Moment — Question 2

Section 28-9 · Physics pages 4634–4635

Question 2 Quasistatic rotation measures the change in dipole potential energy A rigid permanent dipole has fixed moment magnitude mu in uniform field B. An external agent slowly rotates it from theta=30.0 degrees to theta=120 degrees, where theta is measured from B. The dipole starts and finishes at rest; ignore dissipation.⃗ µ θ⃗ B Schematic; labels, not drawing lengths, specify the data. (a) Find the work done by the external agent and by the magnetic torque. (b) Use the energy curvature to classify the aligned and antialigned equilibria.
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Question 2 - Solution Quasistatic rotation measures the change in dipole potential energy⃗ µ θ⃗ B (a) Method and calculation U(θ) = −µB cos θ, Wext = ∆U = µB(cos 30◦−cos 120◦). Wext = √ 3 + 1 2 µB, WB = −Wext. (b) Interpretation and further calculation dU dθ = µB sin θ = 0 at 0, π. U′′(0) = +µB > 0 (stable), U′′(π) = −µB < 0 (unstable). Physical check Zero torque identifies an equilibrium orientation; the energy curvature determines its stability.

Question 2

Quasistatic rotation measures the change in dipole potential energy

A rigid permanent dipole has fixed moment magnitude mu in uniform field B. An external agent slowly rotates it from theta=30.0 degrees to theta=120 degrees, where theta is measured from B. The dipole starts and finishes at rest; ignore dissipation.

Diagram shown in the original SVG worksheet.

  1. Find the work done by the external agent and by the magnetic torque.

  2. Use the energy curvature to classify the aligned and antialigned equilibria.

Question 2 - Solution

Quasistatic rotation measures the change in dipole potential energy

Diagram shown in the original SVG worksheet.

(a) Method and calculation

U(θ)=−μBcos⁡θ,Wext=ΔU=μB(cos⁡30∘−cos⁡120∘).U(\theta)=-\mu B\cos\theta,\quad W_{\mathrm{ext}}=\Delta U=\mu B(\cos30^\circ-\cos120^\circ).Wext=3+12μB,WB=−Wext.W_{\mathrm{ext}}=\frac{\sqrt3+1}{2}\mu B,\quad W_B=-W_{\mathrm{ext}}.

(b) Interpretation and further calculation

dUdθ=μBsin⁡θ=0at 0,π.\frac{dU}{d\theta}=\mu B\sin\theta=0\quad\text{at }0,\pi.U′′(0)=+μB>0 (stable),U′′(π)=−μB<0 (unstable).U\prime\prime(0)=+\mu B>0\text{ (stable)},\quad U\prime\prime(\pi)=-\mu B<0\text{ (unstable)}.

Physical check

Zero torque identifies an equilibrium orientation; the energy curvature determines its stability.