Torque on a Current Loop — Question 5

Section 28-8 · Physics pages 4620–4621

Question 5 Adding turns at fixed voltage can leave torque unchanged when wire resistance also grows A coil has N identical turns, each of area A and perimeter p. The wire has resistivity rho and cross-sectional area s. An ideal voltage source V drives it. The magnetic field and the coil-normal angle theta are fixed; neglect lead resistance. I N turns⃗ B Schematic; labels, not drawing lengths, specify the data. (a) Find the coil current and magnetic torque as functions of N. (b) Compare doubling N under fixed voltage with doubling N under a maintained fixed current.
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Question 5 - Solution Adding turns at fixed voltage can leave torque unchanged when wire resistance also grows I N turns⃗ B (a) Method and calculation RN = ρNp/s, IN = V/RN = V s/(ρNp). τN = NINAB sin θ = V sAB sin θ ρp . (b) Interpretation and further calculation V fixed : I2N = IN/2, τ2N = τN. I fixed : τ2N = 2τN. Physical check Turn count alone does not determine torque; the electrical driving constraint matters.

Question 5

Adding turns at fixed voltage can leave torque unchanged when wire resistance also grows

A coil has N identical turns, each of area A and perimeter p. The wire has resistivity rho and cross-sectional area s. An ideal voltage source V drives it. The magnetic field and the coil-normal angle theta are fixed; neglect lead resistance.

Diagram shown in the original SVG worksheet.

  1. Find the coil current and magnetic torque as functions of N.

  2. Compare doubling N under fixed voltage with doubling N under a maintained fixed current.

Question 5 - Solution

Adding turns at fixed voltage can leave torque unchanged when wire resistance also grows

Diagram shown in the original SVG worksheet.

(a) Method and calculation

RN=ρNp/s,IN=V/RN=Vs/(ρNp).R_N=\rho Np/s,\quad I_N=V/R_N=Vs/(\rho Np).τN=NINABsin⁡θ=VsABsin⁡θρp.\tau_N=NI_NAB\sin\theta=\frac{VsAB\sin\theta}{\rho p}.

(b) Interpretation and further calculation

V fixed:I2N=IN/2,τ2N=τN.V\text{ fixed}:\quad I_{2N}=I_N/2,\quad\tau_{2N}=\tau_N.I fixed:τ2N=2τN.I\text{ fixed}:\quad\tau_{2N}=2\tau_N.

Physical check

Turn count alone does not determine torque; the electrical driving constraint matters.