A Circulating Charged Particle — Question 3

Section 28-5 · Physics pages 4556–4557

Question 3 Helix radius and pitch separately reveal transverse and longitudinal speed A nonrelativistic particle with |q|/m = 107 C/kg moves helically in B=.100 T. Its radius is .0300 m and its pitch, the axial advance per revolution, is .120 m.⃗ B p helix projected onto a plane Schematic; labels, not drawing lengths, specify the data. (a) Find the perpendicular speed, parallel-speed magnitude and total speed. (b) Find the acute angle between velocity and the field, and the number of turns made during an axial advance of .600 m.
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Question 3 - Solution Helix radius and pitch separately reveal transverse and longitudinal speed⃗ B p helix projected onto a plane (a) Method and calculation ω = |q|B/m = 106 s−1, v⊥= ωr = 3.00 × 104 m/s. |v∥| = pω/(2π) = 1.90986 × 104 m/s, v = √ v2 ⊥+ v2 ∥= 3.55634 × 104 m/s. (b) Interpretation and further calculation tan θ = v⊥/|v∥| = 2πr/p ⇒θ = 57.5184◦. N = ∆z/p = .600/.120 = 5.00 turns. Physical check Radius probes only perpendicular momentum; pitch supplies the missing parallel component.

Question 3

Helix radius and pitch separately reveal transverse and longitudinal speed

A nonrelativistic particle with |q|/m=107|q|/m=10^7 C/kg moves helically in B=.100 T. Its radius is .0300 m and its pitch, the axial advance per revolution, is .120 m.

Diagram shown in the original SVG worksheet.

  1. Find the perpendicular speed, parallel-speed magnitude and total speed.

  2. Find the acute angle between velocity and the field, and the number of turns made during an axial advance of .600 m.

Question 3 - Solution

Helix radius and pitch separately reveal transverse and longitudinal speed

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ω=|q|B/m=106s−1,v⟂=ωr=3.00×104m/s.\omega=|q|B/m=10^6\,\mathrm{s^{-1}},\quad v_\perp=\omega r=3.00\times10^4\,\mathrm{m/s}.|v∥|=pω/(2π)=1.90986×104m/s,v=v⟂2+v∥2=3.55634×104m/s.|v_\parallel|=p\omega/(2\pi)=1.90986\times10^4\,\mathrm{m/s},\quad v=\sqrt{v_\perp^2+v_\parallel^2}=3.55634\times10^4\,\mathrm{m/s}.

(b) Interpretation and further calculation

tan⁡θ=v⟂/|v∥|=2πr/p⇒θ=57.5184∘.\tan\theta=v_\perp/|v_\parallel|=2\pi r/p\Rightarrow\theta=57.5184^\circ.N=Δz/p=.600/.120=5.00turns.N=\Delta z/p=.600/.120=5.00\quad\text{turns}.

Physical check

Radius probes only perpendicular momentum; pitch supplies the missing parallel component.