Crossed Fields: The Hall Effect — Question 8

Section 28-4 · Physics pages 4546–4547

Question 8 Four current-field reversals isolate the Hall term from two independent pickup terms Let s and b be signs of applied current and magnetic field. Model four readings as V (s, b) = V0 + sA + bC + sbH, where H is the desired Hall voltage at positive current and field. Measured values in mV are V(+,+)=1.30, V(+,-)=-.70, V(-,+)=-.30 and V(-,-)=.50. I U L y x Bˆz w thickness t along z four settings: (±I, ±B) Hall contacts: VH = VU −VL; current points along +x and the shown field along +z. (a) Construct a signed combination that isolates H and evaluate it. (b) Find V0, A and C and verify one reading from the reconstructed model.
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Question 8 - Solution Four current-field reversals isolate the Hall term from two independent pickup terms I U L y x Bˆz w thickness t along z four settings: (±I, ±B) (a) Method and calculation H = 1 4[V++ −V+−−V−+ + V−−]. H = 1 4[1.30 + .70 + .30 + .50] = .700 mV. (b) Interpretation and further calculation V0 = .200 mV, A = .100 mV, C = .300 mV. V++ = V0 + A + C + H = .200 + .100 + .300 + .700 = 1.30 mV. Physical check The Hall term is odd under either reversal and even under reversing both; the algebra projects out exactly that symmetry.

Question 8

Four current-field reversals isolate the Hall term from two independent pickup terms

Let s and b be signs of applied current and magnetic field. Model four readings as V(s,b)=V0+sA+bC+sbHV(s,b)=V_0+sA+bC+sbH, where H is the desired Hall voltage at positive current and field. Measured values in mV are V(+,+)=1.30, V(+,-)=-.70, V(-,+)=-.30 and V(-,-)=.50.

Diagram shown in the original SVG worksheet.

  1. Construct a signed combination that isolates H and evaluate it.

  2. Find V0, A and C and verify one reading from the reconstructed model.

Question 8 - Solution

Four current-field reversals isolate the Hall term from two independent pickup terms

Diagram shown in the original SVG worksheet.

(a) Method and calculation

H=14[V++−V+−−V−++V−−].H=\tfrac14[V_{++}-V_{+-}-V_{-+}+V_{--}].H=14[1.30+.70+.30+.50]=.700mV.H=\tfrac14[1.30+.70+.30+.50]=.700\,\mathrm{mV}.

(b) Interpretation and further calculation

V0=.200mV,A=.100mV,C=.300mV.V_0=.200\,\mathrm{mV},\quad A=.100\,\mathrm{mV},\quad C=.300\,\mathrm{mV}.V++=V0+A+C+H=.200+.100+.300+.700=1.30mV.V_{++}=V_0+A+C+H=.200+.100+.300+.700=1.30\,\mathrm{mV}.

Physical check

The Hall term is odd under either reversal and even under reversing both; the algebra projects out exactly that symmetry.