Crossed Fields: Discovery of the Electron — Question 8

Section 28-3 · Physics pages 4526–4527

Question 8 A selector isolates velocity while an accelerating voltage couples velocity to charge-to-mass ratio Two positive ion species have masses m and 4m, and charges q and 2q respectively. Both start from rest and must pass the same ideal selector with speed E/B. positive plate negative plate⃗ v⃗ E species (m, q) and (4m, 2q) Schematic; labels, not drawing lengths, specify the data. (a) Find the ratio of accelerating potential magnitudes needed to transmit the two species. (b) If both instead receive the same accelerating potential, find their speed ratio and explain whether both can pass the same force-balanced selector.
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Question 8 - Solution A selector isolates velocity while an accelerating voltage couples velocity to charge-to-mass ratio positive plate negative plate⃗ v⃗ E species (m, q) and (4m, 2q) (a) Method and calculation U1 = m 2q (E B )2 , U2 = 4m 2(2q) (E B )2 . U2/U1 = 2. (b) Interpretation and further calculation v1 = √ 2qU/m, v2 = √ 2(2q)U/(4m) = v1/ √ 2. v1̸ = v2 ⇒both cannot satisfy v = E/B at the same setting. Physical check The selector alone does not measure mass or charge; the accelerating stage supplies the additional relation.

Question 8

A selector isolates velocity while an accelerating voltage couples velocity to charge-to-mass ratio

Two positive ion species have masses m and 4m, and charges q and 2q respectively. Both start from rest and must pass the same ideal selector with speed E/B.

Diagram shown in the original SVG worksheet.

  1. Find the ratio of accelerating potential magnitudes needed to transmit the two species.

  2. If both instead receive the same accelerating potential, find their speed ratio and explain whether both can pass the same force-balanced selector.

Question 8 - Solution

A selector isolates velocity while an accelerating voltage couples velocity to charge-to-mass ratio

Diagram shown in the original SVG worksheet.

(a) Method and calculation

U1=m2q(EB)2,U2=4m2(2q)(EB)2.U_1=\frac m{2q}\left(\frac EB\right)^2,\quad U_2=\frac{4m}{2(2q)}\left(\frac EB\right)^2.U2/U1=2.U_2/U_1=2.

(b) Interpretation and further calculation

v1=2qU/m,v2=2(2q)U/(4m)=v1/2.v_1=\sqrt{2qU/m},\quad v_2=\sqrt{2(2q)U/(4m)}=v_1/\sqrt2.v1≠v2⇒both cannot satisfy v=E/B at the same setting.v_1\ne v_2\Rightarrow\text{both cannot satisfy }v=E/B\text{ at the same setting}.

Physical check

The selector alone does not measure mass or charge; the accelerating stage supplies the additional relation.