What Produces a Magnetic Field? — Question 6

Section 28-1 · Physics pages 4482–4483

Question 6 A small imbalance of aligned microscopic moments can create a macroscopic magnetic source A simplified material contains N = 1020 intrinsic magnetic moments, each of magnitude µa = 9.27 × 10−24 ampere square metre. A fraction f=.600 points along +z and the rest along -z. Treat the net moment as their vector sum. populations fN, (1 −f)N Population sketch only; the number of drawn arrows does not specify f. (a) Find the net moment and the fraction of the fully aligned value. (b) Find the change if f increases to .650 while N remains fixed; explain why no macroscopic transport current is required.
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Question 6 - Solution A small imbalance of aligned microscopic moments can create a macroscopic magnetic source populations fN, (1 −f)N (a) Method and calculation⃗ µnet = [fN −(1 −f)N]µaˆz = Nµa(2f −1)ˆz. µnet = 1.854 × 10−4 A m2, µnet/(Nµa) = .200. (b) Interpretation and further calculation ∆⃗µ = 2Nµa∆f ˆz = 9.27 × 10−5ˆz A m2. Itransport = 0 is compatible with⃗ µnet̸ = 0. Intrinsic moments do not require electrons to be literal rotating charged spheres. Physical check Permanent magnetism can arise from aligned microscopic moments even when the specimen is electrically neutral and carries no transport current.

Question 6

A small imbalance of aligned microscopic moments can create a macroscopic magnetic source

A simplified material contains N=1020N=10^{20} intrinsic magnetic moments, each of magnitude μa=9.27×10−24\mu_a=9.27\times10^{-24} ampere square metre. A fraction f=.600 points along +z and the rest along -z. Treat the net moment as their vector sum.

Diagram shown in the original SVG worksheet.

  1. Find the net moment and the fraction of the fully aligned value.

  2. Find the change if f increases to .650 while N remains fixed; explain why no macroscopic transport current is required.

Question 6 - Solution

A small imbalance of aligned microscopic moments can create a macroscopic magnetic source

Diagram shown in the original SVG worksheet.

(a) Method and calculation

μ→net=[fN−(1−f)N]μaẑ=Nμa(2f−1)ẑ.\vec\mu_{\mathrm{net}}=[fN-(1-f)N]\mu_a\hat z=N\mu_a(2f-1)\hat z.μnet=1.854×10−4Am2,μnet/(Nμa)=.200.\mu_{\mathrm{net}}=1.854\times10^{-4}\,\mathrm{A\,m^2},\quad\mu_{\mathrm{net}}/(N\mu_a)=.200.

(b) Interpretation and further calculation

Δμ→=2NμaΔfẑ=9.27×10−5ẑAm2.\Delta\vec\mu=2N\mu_a\Delta f\hat z=9.27\times10^{-5}\hat z\,\mathrm{A\,m^2}.Itransport=0is compatible withμ→net≠0.I_{\mathrm{transport}}=0\quad\text{is compatible with}\quad\vec\mu_{\mathrm{net}}\ne0.Intrinsic moments do not require electrons to be literal rotating charged spheres.

Physical check

Permanent magnetism can arise from aligned microscopic moments even when the specimen is electrically neutral and carries no transport current.