RC Circuits — Question 5

Section 27-8 · Physics pages 4460–4461

Question 5 A two-stage switch preserves capacitor voltage but changes the exponential law An initially uncharged capacitor charges from a 10.0 V source through R1 for T = R1C ln 2. The source is then disconnected and the capacitor discharges through R2=2R1 only. Let tau=R1C and i=C dvC/dt. t vC T 5 V Schematic; labels, not drawing lengths, specify the data. (a) Write vC(t) before and after T, enforcing continuity. (b) Find the additional time after T to reach 1.00 V and compare i immediately before and after switching.
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Question 5 - Solution A two-stage switch preserves capacitor voltage but changes the exponential law t vC T 5 V (a) Method and calculation 0 ≤t < T : vC = 10(1 −e−t/τ) V, vC(T) = 5.00 V. t ≥T : vC = 5e−(t−T)/(2τ) V. (b) Interpretation and further calculation 1 = 5e−∆t/(2τ) ⇒∆t = 2τ ln 5. i(T −) = (5.00 V)/R1, i(T +) = −(5.00 V)/(2R1). Physical check An ideal switch can change current discontinuously while the capacitor voltage remains continuous.

Question 5

A two-stage switch preserves capacitor voltage but changes the exponential law

An initially uncharged capacitor charges from a 10.0 V source through R1 for T=R1Cln⁡2T=R_1C\ln2. The source is then disconnected and the capacitor discharges through R2=2R1 only. Let tau=R1C and i=C dvC/dt.

Diagram shown in the original SVG worksheet.

  1. Write vC(t) before and after T, enforcing continuity.

  2. Find the additional time after T to reach 1.00 V and compare i immediately before and after switching.

Question 5 - Solution

A two-stage switch preserves capacitor voltage but changes the exponential law

Diagram shown in the original SVG worksheet.

(a) Method and calculation

0≤t<T:vC=10(1−e−t/τ)V,vC(T)=5.00V.0\le t<T:\quad v_C=10(1-e^{-t/\tau})\ \mathrm V,\quad v_C(T)=5.00\,\mathrm V.t≥T:vC=5e−(t−T)/(2τ)V.t\ge T:\quad v_C=5e^{-(t-T)/(2\tau)}\ \mathrm V.

(b) Interpretation and further calculation

1=5e−Δt/(2τ)⇒Δt=2τln⁡5.1=5e^{-\Delta t/(2\tau)}\Rightarrow\Delta t=2\tau\ln5.i(T−)=(5.00V)/R1,i(T+)=−(5.00V)/(2R1).i(T^-)=(5.00\,\mathrm V)/R_1,\quad i(T^+)=-(5.00\,\mathrm V)/(2R_1).

Physical check

An ideal switch can change current discontinuously while the capacitor voltage remains continuous.